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Nana76 [90]
3 years ago
14

The formation of glucose from water and carbon dioxide is an extremely important reaction for life to exist. Plants perform this

reaction through the process of photosynthesis, creating the base of the food chain. The unbalanced reaction is ‍ ‍ ‍ At a particular temperature, the following equilibrium concentrations were found: ‍ M , M , and M . Calculate the value of at this temperature for the reaction that produces mol of glucose.

Chemistry
1 answer:
NemiM [27]3 years ago
3 0

Answer:

Explanation:

Find attach solution

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Using water and the reagents provided in the lab, create two solutions such that when you mix equal amounts together, the result
Bingel [31]

Here’s <em>one of many</em> possibilities.

We <em>MUST</em> know the heat of reaction, Δ<em>H</em>, <em>before we start </em>.

Let’s <em>assume</em> that the reaction is

A + B → Products; Δ<em>H</em> = -80 kJ·mol⁻¹

Let’s <em>assume</em> that you want to get <em>100 mL</em> of solution that warms from <em>25 °C to 50 °C</em>.

<em>For the solution </em>

<em>q = mc</em>Δ<em>T</em> = 100 g × 4.184 J·K⁻¹mol⁻¹ × 25 K = 10 460 J = 10.46 kJ

The reaction must supply 10.46 kJ.

<em>For the reaction</em>

<em>n</em>Δ<em>H</em> = 10.46 kJ

<em>n</em> = 10.46 kJ/80 kJ = 0.131  mol

So, you need <em>0.131 mol A</em> and 0.131 mol B.

<em>Assume</em> you are using the <em>3 mol·L⁻¹ </em>solutions.

Then

<em>V</em> = 0.131 mol × (1 L/3 mol) = 0.0436 L = 46.6 mL

You need 46.6 mL of 3 mol·L⁻¹ A + 46.6 mL of 3 mol·L⁻¹ B.

Add 3.4 mL distilled water to 46.6 mL of 3 mol·L⁻¹ A to make 50 mL of A.

Add 3.4 mL distilled water to<em> </em>46.6 mL of 3 mol·L⁻¹ B to make 50 mL of B.

Mix the two solutions, and you will have 100 mL of a solution at 50 °C .

8 0
4 years ago
How many moles are in 2.5 g of N2<br> O 0089 moles<br> 0.18 moles<br> 13 moles<br> 11 moles
alexgriva [62]
<h2>PRACTICE MULTIPLE CHOICE QUESTIONS FROM UNIT 10</h2>

<h3>1.) A cylinder is filled with 2.00 moles of nitrogen, 3.00 moles of argon, and 5.00 moles of helium. If</h3>

the gas mixture is at STP, what is the partial pressure of the argon?

(A) 152 torr (B) 228 torr (C) 380. torr (D) 760. torr

2.) Compared to the average kinetic energy of 1 mole of water at 0 oC, the average kinetic energy

of 1 mole of water at 298 K is

(A) the same, and the number of molecules is the same

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mercury. If the pressure is changed to 380. millimeters of mercury, at which temperature will

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(A) 100 K (B) 188 K (C) 273 K (D) 546 K

Get the answers to these questions

Back to the Unit 10 Old Tests Page

Back to the Unit 10 Pag

3 0
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