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1 year ago

Based on the map, which area has a scarcity of fresh water?

Physics

2 answers:

Westkost [7]1 year ago

6 0

Answer:

North Africa

Explanation:

Hope this helps

bearhunter [10]1 year ago

5 0

Answer:

Western Europe, South America

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What is the correct definition of pH?

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3 years ago

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An electric immersion heater is put at the bottom of a large tank of water. The water next to the heater becomes warm

djyliett [7]

Answer:

when the water is heated with immersion heater, the water becomes less dense due to which the warm water rises up and the cooler water fills it's space.

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2 years ago

G How much buoyancy force, in N, a person with a mass of 70 kg experiences by just standing in air

sattari [20]

Answer:

686.7N

Explanation:

Given data

Mass= 70kg

We know that the buoyant force experienced by the person is equal to the weight of the person

Hence the weight is

Weight = mass* Acceleration

Weight= 70*9.81

Weight= 686.7N

Therefore the weight is 686.7N

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2 years ago

A 20 kg truck drives in a circle of radius 4 m at 10m/s. What causes

jek_recluse [69]

Answer:

Normal force

Explanation:

The force is centipetral force

Calculating :-

Mass=m=20kg
Radius=r=4m
Velocity=10m/s=v

We know

$\boxed{\sf F_c=\dfrac{mv^2}{r}}$

$\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}$

$\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}$

$\\ \sf\longmapsto F_c=\dfrac{2000}{4}$

$\\ \sf\longmapsto F_c=500N$

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2 years ago

The diameter of 0-gauge copper wire is 8.252 mm. Find the resistance of a 1.00-km length of such wire used for power transmissio

Dafna1 [17]

Answer:

The value is $R = 0.321 \ \Omega$

Explanation:

From the question we are told that

The diameter is $d = 8.252 \ mm = 0.008252 \ m$

The length of the wire is $l = 1.0 \ km = 1000 \ m$

Generally the cross sectional area of the copper wire is mathematically represented as

$A = \pi * \frac{d^2}{4}$

=> $A = 3.142 * \frac{ 0.008252^2}{4}$

=> $A = 5.349 *10^{ - 5} \ m^2$

Generally the resistance is mathematically represented as

$R = \frac{\rho * l }{A }$

Here $\rho$ is the resistivity of copper with the value $\rho = 1.72*10^{-8} \ \Omega \cdot m$

=> $R = \frac{1.72 *10^{-8} * 1000 }{5.349 *10^{ - 5} }$

=> $R = 0.321 \ \Omega$

5 0

2 years ago