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blagie [28]
3 years ago
8

During the push-up, the hips should never hit the ground and should move 1 point

Physics
1 answer:
Monica [59]3 years ago
4 0
Hahahahahahahahahha true
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I added individual steps for clarity. Note that g must be positive if the solution is to be real.

T=2\pi \sqrt{\frac{1}{g}}=2\pi g^{-\frac{1}{2}}\\g^{-\frac{1}{2}} = \frac{T}{2\pi}\\(g^{-\frac{1}{2}})^{-2} = (\frac{T}{2\pi})^{-2}\\g = \frac{4\pi^2}{T^2}\,\,\,, g>0}

Let me know if you have any questions.

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