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blagie [28]
3 years ago
8

During the push-up, the hips should never hit the ground and should move 1 point

Physics
1 answer:
Monica [59]3 years ago
4 0
Hahahahahahahahahha true
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What is the efficiency of a 0.60 kg basketball that, one dropped from a 2.0 m height (from basket rim) , rebounds to 1.2 m in he
Zinaida [17]
<h2>Let us find the efficiency : Ans = 0.6</h2>

Explanation:

we know :

efficiency = output/input

We also know that :

output = m x g x h

where :

m = mass of body

g = acceleration due to gravity

h = height of body from floor

Thus, output = 0.6 x 10 x 1.2 = 7.2J

Similarly ,input = 0.6 x 10 x 2 = 12J

Thus efficiency = 7.2/12 = 0.6

4 0
3 years ago
2. What is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s?
telo118 [61]

Kinetic energy is the energy possessed by an object when that object is moving in space. The higher the mass of an object or higher the speed of an object the higher the kinetic energy will be.

So to calculate the Kinetic Energy we can use the following formula

K.E=(1/2)*m*v^2

Inserting the values in formula gives:

K.E=1/2*7.26*2^2

14.52J

This is the final answer which gives the kinetic energy of the ball.

6 0
3 years ago
Read 2 more answers
What distance does electromagnetic radiation travel in 55.0 μs ?
Komok [63]
Electromagnetic radiation is an energy that is known as light. so electromagnetic radiation will have the same speed as the speed of light which is 3 x 10^8 m/s. so the distance it travel at 55 x 10^-6 s is:
D = ( 3 x 10^8 m/s ) (  55 x 10^-6 s )
D = 16500 m
4 0
3 years ago
You wind a small paper tube uniformly with 153 turns of thin wire to form a solenoid. The tube\'s diameter is 5.11 mm and its le
lina2011 [118]

The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as

L = \frac{\mu N^2 A}{l}

Here,

\mu = Permeability at free space

N = Number of loops

A = Cross-sectional Area

l = Length

Replacing with our values we have,

L = \frac{(4\pi *10^{-7})(153)^2(\pi (\frac{5.11*10^{-3}}{2})^2)}{2.47*10^{-2}}

L = 0.00002442H

L = 24.42\mu H

Therefore the Inductance is 24.42\mu H

3 0
3 years ago
1. Why is it important to use units in any graph?
Scorpion4ik [409]

Answer:

so its easier to understand for the reader

Explanation:

4 0
3 years ago
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