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Likurg_2 [28]
3 years ago
12

Estimate the order of magnitude of the length, in

Physics
1 answer:
Scrat [10]3 years ago
8 0
A) a mouse, to an order of magnitude = 0.1 m ( a tenth of a meter ) That would be a big mouse but the alternatives are 1 meter or one hundredth of a meter... so go with 1/10th 

<span>b) Easy = 1 meter </span>

<span>c) two choices 10m or 100 m . Go with 100 m </span>

<span>d) Stretch it out , trunk tip to tail tip - call it 10 m </span>

<span>e) Your choice 100 m or 1000 m..... These are estimates. So long as you are within one order of magnitude you can't really be given wrong. So I'd say 100m</span>
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A train is traveling at 28 m/s. It slows to 6 m/s in 4 s. Calculate the distance the train
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The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry

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3 years ago
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A weatherman carried an aneroid barometer from the ground floor to his office atop the Sears Tower in Chicago. On the level grou
Sophie [7]

Answer:

442.36038 m or 1451.31362 ft

Explanation:

P_1 = Initial pressure = 30.15 inHg

P_2 = Final pressure = 28.607 inHg

\rho = Density of air  = 0.075 lb/ft³

1\ lb/ft^3=16.0185\ kg/m^3

1\ in=0.0254\ m

1\ m=3.28084\ ft

Density of mercury = 13560 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Difference in pressure is given by

P_1-P_2=\rho gh\\\Rightarrow h=\frac{P_1-P_2}{\rho g}\\\Rightarrow h=\frac{(30.15-28.607)\times 13560\times 0.0254\times 9.81}{0.075\times 16.0185\times 9.81}\\\Rightarrow h=442.36038\ m\\\Rightarrow h=442.36038\times 3.28084\\\Rightarrow h=1451.31362\ ft

The height of the building is 442.36038 m or 1451.31362 ft

4 0
3 years ago
What happens when light passes through a prism or diffraction grating?
Dimas [21]

Answer:

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6 0
3 years ago
What is the car's average velocity (in m/s) in the interval between t = 1.0 s<br> to t = 1.5 s?
natali 33 [55]

Answer:

1.4 m/s

Explanation:

From the question given above, we obtained the following data:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Velocity (v) =..?

The velocity of an object can be defined as the rate of change of the displacement of the object with time. Mathematically, it can be expressed as follow:

Velocity = change of displacement /time

v = Δd / Δt

Thus, with the above formula, we can obtain the velocity of the car as follow:

Initial Displacement (d1) = 0.9 m

Final Displacement (d2) = 1.6 m

Change in displacement (Δd) = d2 – d1 = 1.6 – 0.9

= 0.7 m

Initial time (t1) = 1.5 secs

Final time (t2) = 2 secs

Change in time (Δt) = t2 – t1

= 2 – 1.5

= 0.5 s

Velocity (v) =..?

v = Δd / Δt

v = 0.7/0.5

v = 1.4 m/s

Therefore, the velocity of the car is 1.4 m/s

4 0
3 years ago
How do you do this? Plz help answer
Contact [7]

Answer: Really

Explanation:

Just look it up for this page and maybe you will find an anwser sheet.

7 0
3 years ago
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