He has to travel straight down and maybe get smaller for less wind resistance .
Answer:
See Below.
Explanation:
I can't transpose the diagram onto Brainly. I'll do my best to describe what is going on.
- Draw a horizontal line one inch from the each border of the page.
- To show what each of A and B are supporting, use an up arrow.
- Label the Ends A and B. B is on the right side.
- Put the physics teacher about 1.5 inches from B. His force goes down.
- Label it as 75 * 9.8 Newtons
- Put the platform mass about 2.5 inches from B
- Label it as 10 * 9.8 Newtons
- B is the balance point
- Now put in the distances. The lines are horizontal
- Student A: 10 meters
- Center of mass: 4 meters to B
- Mass of Physics: 2 meters.
Now you are ready to develop the equation
Clockwise
There is only 1 force where B is the Balance point that is going clockwise
10 * Force A
The AntiClockwise Moments
Platform: 4*10kg * 9.8 = 392 N m
Physics T: 2 * 75 * 9.8 = 1470 N m
So the Anti Clockwise moments = the clockwise moments.
10 * Force A = 392 NM + 1470NM Divide by 10. Remember that is in meters
Force A = 1862 N M / 10 10 M = 186 N
Does that make some sort of sense? It should Student A is the furthest distance from where all the action is at B. Therefore he is carrying the lightest weight.
Now what is the total force?
(75 + 10 ) * 9.8 = 85 * 9.8 = 833
This is one of those strange things that won't make sense until it does. Read the next sentence carefully. B is carrying most of the weight. Remember Newtons measure weight.
Support of A = 186 N
Support of B = x
Total of A+B = 933
186 + x = 833
x = 933 - 186
x = 647
So the forces are
A supports 186
B supports 647
Fluid mechanics deals with pressure and internal forces in the fluid. So the correct answer should be a) how fluids do work.
If you put two solids in contact, there will be a contact force created between them. Since Pressure = Force / Area, the correct answer should be b) exert pressure on each other.
Normal force is the force exerted when an object is on an surface. So an example could be a pile of books on top of a table.
Answer:
The period of the telescope observe the light flashes is 1.2 sec.
(e) is correct option.
Explanation:
Given that,
Flashes of light = 1 sec
Speed of telescope =0.6c
We need to calculate the period of the telescope observe the light flashes
Using formula of period
Put the value into the formula
Hence, The period of the telescope observe the light flashes is 1.2 sec.