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dmitriy555 [2]
4 years ago
11

How is a warm front differnt from a cold front

Physics
1 answer:
NISA [10]4 years ago
8 0
Bruh... but a warm front is different because it brings warm ness and sun, a cold front brings clouds , cloudy weather, and cold weather
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If a body of 2kg mass is at a distance of 7200km from the center of the earth .What
wlad13 [49]

None of the choices is correct.

== The Earth's radius is 6,371 km.  That's how far you are from the center of the Earth when you're on the ground.

== The acceleration of gravity on the ground is 9.8 m/s² .

== The acceleration of gravity varies inversely as the square of the distance from the center of the Earth.  So, at 7,200 km from the center, it's

(9.8 m/s²) · (6371km/7200km)² .

Stuffing this through your cakulator, you'll get  <em>7.67 m/s²</em> .

3 0
3 years ago
Spinning situations???
Papessa [141]
Just like mass, energy, linear momentum, and electric charge, angular momentum is also conserved.

The wheel has angular momentum.  I don't remember whether it's
up or down (right-hand or left-hand rule), but it's consistent with
counterclockwise rotation as viewed from above.

When you grab the wheel and stop it from spinning (relative to you),
that angular momentum has to go somewhere.

As I see it, the angular momentum transfers through you as a temporary
axis of rotation, and eventually to the merry-go-round. Finally, all the mass
of (merry-go-round) + (you) + (wheel) is rotating around the big common
axis, counterclockwise as viewed from above, and with the magnitude
that was originally all concentrated in the wheel.
7 0
4 years ago
Read 2 more answers
if you apply a Force of F1 to area A1 on one side of a hydraulic jack, and the second side of the jack has an area that is twice
Firlakuza [10]

Answer:

2F_{1}

Explanation:

F₁ = Force on one side of the jack

A₁ = Area of cross-section of one side of the jack

F₂ = Force on second side of the jack

A₂ = Area of cross-section of second side of the jack = 2 A₁

Using pascal's law

\frac{F_{1}}{A_{1}}= \frac{F_{_{2}}}{A_{_{2}}}

\frac{F_{1}}{A_{1}}= \frac{F_{_{2}}}{2A_{_{1}}}

F_{1}= \frac{F_{2}}{2}\\

F_{2}= 2F_{1}

7 0
4 years ago
A Juggler is juggling a uniform rod one end of which is coated in tar and burning. He is holding the rod by the opposite end and
lyudmila [28]

The vertical speed of the rod varies inversely as the rotational speed for a given number of complete rotations

The equation that gives the vertical velocity, v₀ is  \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Reason:

<em>From a similar question, the given parameters appear to be correctly given as follows;</em>

<em>The vertical speed of the rod = v₀</em>

<em>Angular velocity of the = ω₀</em>

Required;

The value of, v₀, so that the rod has made exactly, <em>n</em>, number of turns when it returns to his hand

Where;

n = An integer

Solution;

The time the rod spends in the air is given as follows;

Height, \ h = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

Where;

g = Acceleration due to gravity

t = Time of motion

When the rod returns to his hand, we have, h = 0, therefore;

0 = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

u \cdot t = \dfrac{1}{2} \cdot g \cdot t^2

t^2 =  \dfrac{u \cdot t }{\dfrac{1}{2} \cdot g } =   \dfrac{2 \cdot u \cdot t }{g }

Time, \ t =    \dfrac{2 \cdot u  }{g }

We have;

Angular \ velocity, \ \omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{t} \ (required)

\omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{  \dfrac{2 \cdot v_0  }{g }} =  \dfrac{ g \cdot \pi \cdot n}{  v_0 }

Therefore;

The \ vertical \ velocity, \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Learn more here:

brainly.com/question/14140053

4 0
3 years ago
Which of the following represents a system that is completely open
Softa [21]
The boiling pot of water is completely open 
4 0
3 years ago
Read 2 more answers
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