Answer:
K = 9.59x10⁻⁴ m/bar
Explanation:
To do this, we need to write the Henry's law which is the following:
C = P*K (1)
K is the constant of the henry's law
C is the concentration of the solution
P is the pressure.
We have data for pressure which is 0.968 bar, and we need to calculate the concentration.
Concentration of any solution is calculated with the expression of molarity, which is:
C = n/V (2) m = n/kg water
The volume of this solution, will be the volume of water. Assuming density of water = 1 g/mL we can say that 500 g of water = 500 mL of water or 0.5 kg of water. But this is a solvent, so, we will calculate the molality instead of molarity
The moles are calculated with:
n = m/MM (3)
The molar mass of CO is:
MM CO = 12 + 16 = 28 g/mol
Now, let's use expression (3), (2) and finally the (1) to get the constant:
n = (13/1000) / 28 = 4.64x10⁻⁴ moles
Using expression (2), we will calculate the molality:
m = 4.64x10⁻⁴ / 0.5 = 9.28x10⁻⁴ m
Finally, from (1) we solve for K:
K = C/P
K = 9.28x10⁻⁴ / 0.968
K = 9.59x10⁻⁴ m/bar
