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Alex Ar [27]
4 years ago
5

A _______ ________is a machine that does work with only one movement of the machine

Physics
1 answer:
irga5000 [103]4 years ago
7 0

simple machine is your answer

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A high fountain of water is located at the center of a circular pool. Not wishing to get his feet wet, a student walks around th
Alisiya [41]

Answer:

The fountain is 3.43 m high.

Explanation:

Circumference of the pool = 15 m.

C = 2\pir

where C is the circumference and r its radius.

r = \frac{C}{2\pi }

 = \frac{15}{2(\frac{22}{7}) }

r = 2.3864

radius of the pool = 2.40 m

So that the height of the fountain, h, can be determined by applying trigonometric function.

Tan θ = \frac{opposite}{adjacent}

Tan 55 = \frac{h}{2.4}

h = Tan 55 x 2.4

  = 1.4282 x 2.4

  = 3.4277

h = 3.43 m

The height of the fountain is 3.43 m.

8 0
3 years ago
If a light bulb is missing or broken in a parallel circuit, will the other light bulb right ?
Nataly [62]

No because the path the electricity needs to follow is broken. In parallel circuit,electricity has more that one path to follow.
7 0
3 years ago
Hell please thanks!!!!!!’
Slav-nsk [51]

Answer:

liquid phase

Explanation:

it is liquid phase because molecules are not that tightly packed as solid and not that far away from each other as in gas phase.

5 0
3 years ago
Could you please help me on number four
sleet_krkn [62]
What is it asking? It is sort of blurry
3 0
3 years ago
Part D- Isolating a Variable with a Coefficient In some cases, neither of the two equations in the system will contain a variabl
Shtirlitz [24]

Answer:

D)     D = \frac{5}{4}  - \frac{3}{4} \ C, E)  (C, D) = ( \frac{17}{7}, \ \frac{-4}{7}

Explanation:

Part D) two expressions are indicated

          3C + 4D = 5

          2C +5 D = 2

let's simplify each expression

         3C + 4D = 5

         4D = 5 - 3C

we divide by 4

            D = \frac{5}{4}  - \frac{3}{4} \ C

The other expression

       2C +5 D = 2

       2C = 2 - 5D

        C = 1 -  \frac{5}{2} \ D

we can see that the correct result is 1

Part E.

It is asked to solve the problem by the substitution method, we already have

          D =  \frac{5}{4}  - \frac{3}{4} \ C

we substitute in the other equation

            2C +5 D = 2

             2C +5 (5/4 - ¾ C) = 2

we solve

            C (2 - 15/4) + 25/4 = 2

             -7 / 4 C = 2 - 25/4

             -7 / 4 C = -17/4

              7C = 17

               C = \frac{17}{7}

now we calculate D

               D = \frac{5}{4} - \frac{3}{4} \ \frac{17}{7}

               D = 5/4 - 51/28

               D =\frac{35-51}{28}

               D = - 16/28

               D = - \frac{4}{7}

the result is (C, D) = ( \frac{17}{7}, \ \frac{-4}{7} )

8 0
3 years ago
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