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Nataly [62]
2 years ago
8

Two concentric, coplanar, circular loops of wire of different diameter carry currents in the same direction. Describe the nature

of the force exerted on the inner loop by the outer loop and on the outer loop by the inner loop.
Physics
1 answer:
Ierofanga [76]2 years ago
4 0

Answer:

Both will be attractive in nature.

Explanation:

In the given case, the direction of the magnetic field is same in both loops as the direction of the current is same in both loops. When two parallel straight wire carrying current in the same direction are brought close to each other, the force between them is attractive in nature. In the same way,  when two coplanar, circular and concentric loops of wire are carrying current in the same direction, the force between them is attractive in nature. It can be checked by using right hand thumb rule.

Check out other explanations.

brainly.com/question/15555539

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Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1.0 mm.
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Answer:

R_a/R_b=3

Explanation:

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R=pL/A

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A_a=πr^2_a

A_a=πd^2_A/4

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R_a=(4*p*L_a)/π*d^2_A                                     (1)

the area of the second wire is:  

A_b=π*r^2_B,σ-π*r^2_B,i

A_b=π/4(d^2_B,σ-d^2_B,i)

hence the resistance is:  

R_b=(4*p*L_b)/π(d^2_B,σ-d^2_B,i)                   (2)

To find the ratio between the resistances R_a/R_b, we divide (1) over (2) to get:  

R_a/R_b=(d^2_B,σ-d^2_B,i)*L_a/(d^2_a*L_b)

but the wires have the same length, therefore:  

R_a/R_b=(d^2_B,σ-d^2_B,i)/(d^2_a)

substitute with the given values to get:

R_a/R_b=3

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