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4 years ago

Short Answer

Physics

1 answer:

liq [111]4 years ago

5 0

Answer:

pork, crustaceans, blood, non-halal animal-derived additives such as gelatin or suet, alcohol and any foods containing alcohol as an ingredient

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What Is the definition of the term gravitational potential energy

OLga [1]

Answer:

Here are all the possible meanings and translations of the word gravitational energy. Gravitational energy is the potential energy associated with the gravitational field. This phrase is found frequently in scientific writings about quasars and other active galaxies. Quasars generate and emit their energy from a very small region.

Explanation:

4 0

3 years ago

When dolphin swims close to its prey, it transmits sound waves to figure out details (like direction where the fish is moving) o

svet-max [94.6K]

Answer:

The frequency of the waves depends on the distance between wave fronts - considering a front as a maximum disturbance of the wave

(Consider the waves emitted by an organ pipe: condensation and rarefactions)

The waves themselves are a fixed distance apart -

as one moves towards the source the waves received will be closer together (higher frequency)

So if the frequency received increases, the distance between the source and the observer must be decreasing

8 0

3 years ago

A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. W

Tamiku [17]

<h2>Answer</h2>

Radius is 421 m.

<u>Explanation </u>

A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,

As mass = m = 1500kg,

Centripetal force = Fc = 640N,

Velocity = v = 13.4 m / s

By putting values, Fc = mv ^ 2 / r,

r = mv ^ 2 / Fc,

=> r = ( 1500kg ) . ( 13.4 m / s) ^ 2 / 640,

=> r = ( 1500kg ) . ( 179.56 ) / 640,

r = 269340 / 640,

=> r = 420.84 m.

Radius is 421 m.

8 0

3 years ago

Read 2 more answers

Which has the greater acceleration

Alik [6]

Answer: Object B

The velocity of object A is depicted in the graph as a straight line (constant speed therefore no acceleration).
The graph indicates that the velocity of object B increases (the object is accelerating).

5 0

3 years ago

Problem 4 A meteoroid is first observed approaching the earth when it is 402,000 km from the center of the earth with a true ano

Nikitich [7]

Answer:

Part a: The eccentricity is 1.086.

Part b: The altitude at closest approach is 5088 km

Part c: The velocity at perigee is 8.516 km/s

Part d: The turn angle is 134.08 while the aiming radius is 5641.28 km

Explanation:

Specific energy is given by

$\epsilon=\frac{v^2}{2}-\frac{\mu}{r}$

Here

ε is the specific energy
v is the velocity which is given as 2.23 km/s
μ is the gravitational constant whose value is 398600
r is the distance between earth and the meteorite which is 402,000 km

$\epsilon=\frac{v^2}{2}-\frac{\mu}{r}\\\epsilon=\frac{2.2^2}{2}-\frac{398600}{402,000}\\\epsilon=1.495 km^2/s^2$

Value of specific energy is also given as

$\epsilon=\frac{\mu}{2a}\\a=\frac{\mu}{2\epsilon}\\a=\frac{398600}{2\times 1.495}\\a=13319 km$

Orbit formula is given as

$r=a(\frac{e^2-1}{1+ecos \theta})\\ae^2-recos\theta-(a+r)=0$

Putting values in this equation and solving for e via the quadratic formula gives

$ae^2-recos\theta-(a+r)=0\\(133319)e^2-(402000)(cos 150) e-(133319+402000)=0\\133319e^2+348142.21 e-535319=0\\\\e=\frac{-348142.21 \pm \sqrt{348142.21^2-4(133319)(535319)}}{2 (133319)}\\\\e=1.086 \, or \, -3.69$