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makkiz [27]
3 years ago
9

24.08 x 10^23 atoms of Boron (B) is equal to how many moles of Boron?

Chemistry
2 answers:
Naddika [18.5K]3 years ago
6 0

Answer:

4 moles.

Explanation:

We know that the number of atoms in a mole of a substance = Avagadro's number = 6.023X10^{23}

the moles of boron containing 24.08X10^{23} atoms will be:

moles=\frac{numberofboronatoms}{avagadro'snumber}=\frac{24.08X10^{23}}{6.023X10^{23}}=3.99=4

Thus there will be four moles in the given atoms of boron.

padilas [110]3 years ago
5 0
1 mole ----------- 6.02 x 10²³ atoms
? mole ---------- 24.08 x 10²³ atoms

moles B = ( 24.08 x 10²³) x 1 / 6.02 x 10²³

moles B = 24.08 x 10²³ / 6.02 x 10²³

= 4 moles

Answer B

hope this helps!
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