Answer:
Copper(II) sulphate – sodium hydroxide reaction
The reaction between copper(Il) sulphate and sodium hydroxide solutions is a good place to start. If you slowly add one to the other while stirring, you will get a precipitate of copper(II) hydroxide, Cu(OH)2.
Answer:
Chemical reactions do not involve changes in the chemical bonds that join
atoms in compounds :
<u>False</u>
Explanation:
Chemical reaction are the reaction in which old bonds break and new bonds are formed . The formation of new bond result in formation of new compounds . This happen because new bond are result of linking different atoms by the bond.
For example : Water formation from Oxygen and Hydrogen is a chemical process :

Original(old) bonds are :
H-H bond in H2 and O-O bonds in O2
In H2 = Hydrogen is joined to Hydrogen
IN O2 = Oxygen is joined to oxygen
New Bonds =
O-H bonds in water (H2O)
Oxygen is joined to hydrogen = New Bond formation
Hence,
<u>Chemical reactions do involve changes in the chemical bonds that join
</u>
<u>atoms in compounds</u>
<u />
Answer:
The stronger electrolyte is the HCl
Explanation:
Stronger electrolyte are the ones, that in water, completely dissociates.
HCl(aq) → H⁺(aq) + Cl⁻(aq)
HCl(aq) + H₂O(l) → H₃O⁺ (aq) + Cl⁻(aq)
Both are acids, they bring protons to medium but the hydrochloric completely dissociates.
HF (aq) + H₂O(l) ⇄ H₃O⁺(aq) + F⁻(aq) Ka
In the dissociation of weak electrolytes, they ionize but at the same time they bond again, so the reaction is always kept in equilibrium.
Answer:
No. of neutrons = 27 - 13 = 14
No. of protons = No. of electrons = 13
Hope it helps you
Answer:
697 g / mol
Explanation:
The osmotic pressure of a protein ( non electrolyte ) is given by:
π V= nRT where V is the volume, n is the number of moles, R is the gas constant ( 0.08206 L·atm/Kmol ), and T is the temperature (K).
n= mass/ MW protein ⇒ MW protein = mass / n
Thus,
π V = ( mass/ MW ) RT
MW = mass x R xT/ ( π V )
mass = 0.873 g
R = 0.08206 L·atm/K·mol
T = ( 15.6 + 273 ) K= 288.6 K
π = 0.061 atm
V = 48.6 mL = 48.6 mL x ( 1 L/ 1000 mL ) = 0.0486 L
We just need to plug our values into the aqbove equation for MW:
MW = 0.873 g x 0.08205 L· atm /K·mol x 288.6 K / ( 0.061 atm x0.0486 L )
= 697 g/mol