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Sladkaya [172]
3 years ago
13

Study the image

Chemistry
2 answers:
Ronch [10]3 years ago
8 0

Answer:

The correct answer is Cirrocumulus.

Explanation:

Cirrocumulus : Clouds forming broken layer of small fleecy clouds at higher altitudes.

Cumulonimbus  : Clouds forming a towering mass with flat base with flat base at lower altitude

Cumulus  : Cloud forming rounded masses heaped or stacked on each other above a flat base , fairly at lower altitudes.

Stratus : Clouds forming continuous horizontal gray sheet, usually during rain or snow.

The given image corresponds to description given as Cirrocumulus.

evablogger [386]3 years ago
5 0

Answer:

A

Explanation:

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Answer:

animals unlike us adapt faster to heat/cool weather or water

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3 years ago
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An aqueous KNO3 solution is made using 76.6 g of KNO3 diluted to a total solution volume of 1.84 L. (Assume a density of 1.05 g/
defon

Answer:

The answer to your question is Molarity = 0.41

Explanation:

Data

mass of KNO₃ = 76.6 g

volume = 1.84 l

density = 1.05 g/ml

Process

1.- Calculate the molecular mass of KNO₃

molecular mass = 39 + 14 + (16 x 3) = 101 g

2.- Calculate the number of moles

                      101 g of KNO₃  --------------- 1 mol

                       76.6 g of KNO₃ ------------  x

                        x = (76.6 x 1) / 101

                        x = 0.76 moles

3.- Calculate molarity

Molarity = \frac{number of moles}{volume}

Substitution

Molarity = \frac{0.76}{1.84}

Result

Molarity = 0.41

7 0
3 years ago
To what class of minerals do gold, silver, and copper belong?
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What does the second law of thermodynamics say? O A. The entropy of the universe is increasing. B. A system at equilibrium has n
gayaneshka [121]

Answer:

A.  The entropy of the universe is increasing.(always)

Explanation:

The Second Law of Thermodynamics states that Entropy cannot decrease, because it keeps increasing and increasing and increasing. It will always stay on the increasing side.

<u><em>Hope this helps!</em></u>

<u><em>Please Mark Brainliest!</em></u>

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