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Answer:
O2+ e-→O2-εo’= -0.040 V+ 0.046 V= -0.925 Vb. Q = 1/0.02 = 50,the number of electrons transferred νe= 1, ε’=εo’-(0.0591V/νe)*logQ = -0.971V –0.0591V*log50 = -1.071 V
Explanation:
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Answer:)
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