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Brilliant_brown [7]
3 years ago
6

PLZ HELP WILL GIVE BRAINLIEST

Chemistry
2 answers:
Marrrta [24]3 years ago
6 0

Answer:

The answer is A

Explanation:

I checked on a temperature converter calculator.

atroni [7]3 years ago
5 0

Answer:

100 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

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A 96.0 ml volume of 0.25 m hbr is titrated with 0.50 m koh. calculate the ph after addition of 48.0 ml of koh at 25 ∘c.
PilotLPTM [1.2K]
KOH is a strong base and HBr is a strong acid and completely dissociates.
The balanced equation for the reaction is;
KOH + HBr ---> KBr + H₂O
Stoichiometry of acid to base is 1:1
The number of KOH moles reacted - 0.50 M / 1000 mL/L x 48.0 mL = 0.024 mol
number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL  = 0.024 mol
the number of H⁺ ions are equal to number of OH⁻ ions. 
Then the solution is neutral.
pH of neutral solutions at 25 °C is 7. 
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8 0
3 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

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