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Free_Kalibri [48]
3 years ago
8

The speed of a sound wave

Physics
2 answers:
Len [333]3 years ago
5 0

B. Depends on the medium.

valina [46]3 years ago
4 0

Answer:

B) the medium

Explanation:

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For each pair of vehicles, choose the vehicle that would experience the greatest force of impact in a collision. Type your answe
velikii [3]

Answer:

I need help on this tooo

Explanation:

8 0
3 years ago
Can Anyone Some one Help me with these three Questions PLEASE!!!!
pentagon [3]
1) is the first one : the populations become adapted to different environments and eventually become so different that they cannot interbreed to produce fertile offspring

2) is the third one : they have identical physical characteristics

3) is the second one : the populations are isolated and thus do not interbreed .

hoped it helped !!!
4 0
3 years ago
The temperature of a plastic cube is monitored while the cube is pushed 3.4 m across a floor at constant speed by a horizontal f
Nesterboy [21]

Answer:

\Delta E_{floor} = 51 J

Explanation:

The work (W) done on the cube to be pushed across the floor is equal to the total thermal energy (ΔE) of the system:        

W = \Delta E_{T} = \Delta E_{cube} + \Delta E_{floor} (1)

Also, the work done on the cube by the horizontal force is giving by:

W = F \cdot d (2)  

<em>where F: force applied to the cube , d: displacement of the cube     </em>    

<em>By equaling the equations (1) and (2)</em>, we can find the thermal energy of the floor:  

\Delta E_{cube} + \Delta E_{floor} = F \cdot d

\Delta E_{floor} = F \cdot d - \Delta E_{cube}

\Delta E_{floor} = 20 N \cdot 3.4 m - 17 J  

\Delta E_{floor} = 51 J

 

So, the increase in the thermal energy of the floor is 51 J.  

Have a nice day!    

7 0
3 years ago
Ricardo is on vacation, doing some mountain climbing. He notices that the higher he goes up a mountain, the colder he feels. He
Irina-Kira [14]

Answer:

B. an inverse relationship

Explanation:

Here is the complete question

Ricardo is on vacation, doing some mountain climbing. He notices that the higher he goes up a mountain, the colder he feels. He remembers his physics teacher teaching about these types of relationships. What is the type of relationship between mountain elevation and temperature? A. a positive relationship B. an inverse relationship C. a neutral relationship D. a direct relationship

Solution

It is an inverse relationship because, as Ricardo's mountain elevation increases, he feels colder. So, as his mountain elevation increases, the temperature decreases.

Since one variable decreases while the other increases, it can only be an inverse relationship.

Let h be Ricardo's mountain elevation and T his temperature. So by inverse proportionality,

h ∝ 1/T

h = k/T

hT = k = constant

So, we have an inverse relationship and B is the answer.

8 0
3 years ago
Read 2 more answers
UN ELEVADOR DE TALLER TIENE PISTONES DE ENTRADA Y DE SALIDA , CON DIAMETRO DE 15 cm Y 40 cm RESPECTIVAMENTE, SE USA EL ELEVADOR
Studentka2010 [4]

Answer:

a) La fuerza que se aplica al pistón de entrada tiene una magnitud de 1968.75 newtons.

b) La presión que se aplica al pistón de entrada es de 111408.460 pascales.

Explanation:

a) Este problema se resuelve mediante el Principio de Pascal, el cual establece que la presión dentro de un sistema hidráulico cerrado es la misma en cualquiera de sus puntos. Por tanto, podemos calcular la fuerza aplicada al pistón de entrada mediante la siguiente relación:

\frac{F_{in}}{\frac{\pi}{4}\cdot D_{in}^{2}} = \frac{M\cdot g}{\frac{\pi}{4}\cdot D_{out}^{2} }

F_{in} = \left(\frac{D_{in}}{D_{out}} \right)^{2}\cdot M\cdot g (1)

Where:

F_{in} - Fuerza aplicada al pistón de entrada, en newtons.

D_{in} - Diámetro del pistón de entrada, en metros.

D_{out} - Diámetro del pistón de salida, en metros.

M\cdot g - Peso del carro, en newtons.

Si sabemos que D_{in} = 0.15\,m, D_{out} = 0.40\,m y M\cdot g = 1.4\times 10^{4}\,N, entonces la fuerza aplicada al pistón de entrada es:

F_{in} = \left(\frac{0.15\,m}{0.40\,m} \right)^{2}\cdot (1.4\times 10^{4}\,N)

F_{in} = 1968.75\,N

La fuerza que se aplica al pistón de entrada tiene una magnitud de 1968.75 newtons.

b) Ahora, presión aplicada al pistón de entrada (p), en pascales, queda descrita a través de la siguiente expresión:

p = \frac{F_{in}}{\frac{\pi}{4}\cdot D_{in}^{2} } (2)

Si sabemos que F_{in} = 1968.75\,N y D_{in} = 0.15\,m, entonces la presión aplicada al pistón de entrada es:

p = \frac{1968.75\,N}{\frac{\pi}{4}\cdot (0.15\,m)^{2} }

p = 111408.460\,Pa

La presión que se aplica al pistón de entrada es de 111408.460 pascales.

3 0
3 years ago
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