Answer:
No. of Molecules = 18.06 x 10²³ molecules
No. of Atoms of P = 3 atoms
No. of Atoms of Na = 9 atoms
Total No. of Atoms = 24 atoms
Explanation:
<u>FOR NUMBER OF MOLECULES</u>:

<u>No. of Molecules = 18.06 x 10²³ molecules</u>
<u></u>
<u>FOR NUMBER OF P ATOMS</u>:

<u>No. of Atoms of P = 3 atoms</u>
<u></u>
<u>FOR NUMBER OF Na ATOMS</u>:

<u>No. of Atoms of Na = 9 atoms</u>
<u></u>
<u>FOR TOTAL NUMBER OF ATOMS</u>:

<u>Total No. of Atoms = 24 atoms</u>
<u></u>
<u></u>
Answer:
Explanation:
For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit , these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.
option b is correct.
With this load, the fraction of the average power, put out by the source of emf, delivered to the load can be calculated as follows
Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor. So the correct option is .7
option D ) is correct.
The net force on the system:
F = m₂g - m₁gsin(∅)
F = 39.5 x 9.81 - 43 x 9.81 x sin(30)
F = 176.58 N
Now, we use F = ma to find the acceleration on each mass.
F = m₁a₁
a₁ = 176.58 / 43
a₁ = 4.11 m/s²
F = m₂a₂
a₂ = 176.58 / 39.5
a₂ = 4.47 m/s²
To solve this problem it is necessary to apply the concepts related to Ohm's Law to find the voltage in the case of direct current. While for the Alternate current we use the concept of RMS voltage.
PART A) In the case of DC we have to,
V=IR
Where,
I = Current
R = Resistance
Where the current is 60mA y the resistance is
, then the potential would be


In the case of DC we have that the current and the RMS voltage is,



The potential in AC then is,



Answer:
I believe it's A. An installment credit has an interest rate, repayment terms and fees, and fixed payment.