Volume is

Calcium Oxide will react with ammonium chloride to produce ammonia gas, water vapor, and calcium chloride. If only 16.3 g of amm

Vaselesa [24]

Answer:

%age Yield = 22.72 %

Explanation:

The balance chemical equation is as follow;

2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O

Step 1: <u>Calculate Moles of CaO, NH₄Cl and NH₃;</u>

CaO:

Moles = Mass / M.Mass

Moles = 112 g / 56.07 g/mol

Moles = 1.99 moles of CaO

NH₄Cl:

Moles = Mass / M.Mass

Moles = 224 g / 53.49 g/mol

Moles = 4.18 moles of NH₄Cl

NH₃:

Moles = Mass / M.Mass

Moles = 16.3 g / 17.03 g/mol

Moles = 0.95 moles of NH₃

Step 2: <u>Calculate Limiting reagent as:</u>

According to equation.

2 moles of NH₄Cl reacts with = 1 mole of CaO

So,

4.18 moles of NH₄Cl will react with = X moles of CaO

Solving for X,

X = 4.18 mol × 1 mol / 2 mol

X = 2.09 mol of CaO

This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.

Step 3: <u>Calculate Theoretical Yield of NH₃ as;</u>

According to equation.

2 moles of NH₄Cl produced = 2 moles of NH₃

So,

4.18 moles of NH₄Cl will produce = X moles of NH₃

Solving for X,

X = 4.18 mol × 2 mol / 2 mol

X = 4.18 mol of NH₃

Step 4: <u>Calculate Percentage Yield as;</u>

%age Yield = Actual Yield / Theoretical Yield × 100

%age Yield = 0.95 mol / 4.18 × 100

%age Yield = 22.72 %

5 0

3 years ago

Problem PageQuestion A chemistry student needs 10.0g of dimethyl sulfoxide for an experiment. By consulting the CRC Handbook of

PIT_PIT [208]

Answer:

9.09cm3

Explanation:

The following data were obtained from the question:

Mass of dimethyl sulfoxide = 10g

Density of dimethyl sulfoxide = 1.10gcm−3

Volume of dimethyl sulfoxide =?

The density of a substance is simply the mass substance per unit volume of the substance. It is represented mathematically as:

Density = Mass/volume.

With the above formula, we can obtain the volume of dimethyl sulfoxide as follow:

Density = Mass/volume

1.10gcm−3 = 10g/ volume

Cross multiply to express in linear form

1.10gcm−3 x Volume = 10g

Divide both side by 1.10gcm−3

Volume = 10g / 1.10gcm−3

Volume = 9.09cm3

Therefore, the volume of dimethyl sulfoxide the student should pour out is 9.09cm3

7 0

4 years ago

PLEASE HELP ME ASAPP!!

aliina [53]

Conduction-

putting an icepack on injury

grabbing a warm coffee mug

burning yourself by touching boiling water

the handle of a pot being to hot to touch

Convection-

heat from a fire to warm hands

warm water rising to the surface of of the ocean etc.

warm air rising off pavement

an oven that cooks by cycling warm air through the bottom and out the top

Radiation-

cooking popcorn using microwave

heat from the sun hitting a solar panel

( i havent done science in a while cuz im homeschooled but i think most of these are correct)

good luck on what your working on !!

7 0

3 years ago

in this trial, 0.400 M NaOH was added to 40.00 ml of 0.400 M HCl. How many ml of base must be added to cause the colour to chang

denis-greek [22]

Answer:

The amount of Ml that is needed

6 0

3 years ago

A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo

Afina-wow [57]

The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>

Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

= (2.684 - 2.156) g

= 0.528 g

Find the number of moles of the elements in the compound

The number of moles is given by

$n = \frac{m}{M}$

where m = given mass and

M = Molar mass

Number of moles of Zinc = $\frac{2.156}{65}$ = 0.033 moles

Number of moles of Oxygen = $\frac{0.528}{16}$ = 0.033 moles

Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

brainly.com/question/1603500

#SPJ4

5 0

1 year ago