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netineya [11]
3 years ago
7

Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon

monoxide and hydrogen: C3H8(g)+3H2O(g)→3CO(g)+7H2(g) In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide: CO(g)+H2O(g)→H2(g)+CO2(g) Write the net chemical equation for the production of hydrogen from propane and water. Be sure your equation is balanced.
Chemistry
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

Explanation:

First equation:

The reactants propane and water  react to form the products CO and H2

C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)

Second equation:

The products CO and H2 will react

CO(g) + H2O(g) → H2(g) + CO2(g)

We should multiply the equation by 3 (to equal the products of the first equation)

3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)

Add the second to the first equation:

C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

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Which of the following happens when a reaction reaches dynamic equilibrium in a closed system? The concentrations of the reactan
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A chemistry graduate student is given of a pyridine solution. Pyridine is a weak base with . What mass of should the student dis
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34.1g of C₅H₅NHCl the student need to dissolve to the solution.

Explanation:

Full question is:

A chemistry graduate student is given 500.mL of a 0.20M pyridine C5H5N solution. Pyridine is a weak base with =Kb×1.7x10−9 . What mass of C5H5NHCl should the student dissolve in the C5H5N solution to turn it into a buffer with pH =4.76 ?

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pOH = pKb + log [BH⁺] / [B]

<em>Where pKb is -log Kb = 8.77, </em>[BH⁺] concentration of C₅H₅NHCl and [B] concentration of C₅H₅N (It is possible to take the moles of both compounds and not its concentration.

As pH the student wants is 4.76, pOH is:

pOH = 14 - pH = 14 - 4.76 = 9.24

Replacing:

9.24 = 8.77 + log [C₅H₅NHCl] / [C₅H₅N]

Moles of C₅H₅N are:

0.500L × (0.20mol / L) = 0.10mol C₅H₅N

Replacing again:

9.24 = 8.77 + log [C₅H₅NHCl] / [0.10mol]

2.9512 = [C₅H₅NHCl] / [0.10mol]

0.29512 moles = [C₅H₅NHCl].

As molar mass of C₅H₅NHCl is 115.56g/mol, mass of 0.29512 moles are:

0.29512 moles C₅H₅NHCl × (115.56g / mol) =

<h3>34.1g of C₅H₅NHCl the student need to dissolve to the solution.</h3>

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