Which of the following compounds is the most soluble in water?
1 answer:
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<u>Answer:</u> The below calculations proves that the rate of diffusion of is 0.4 % faster than the rate of diffusion of
<u>Explanation:</u>
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:
We are given:
Molar mass of
Molar mass of
By taking their ratio, we get:
From the above relation, it is clear that rate of effusion of is faster than
Difference in the rate of both the gases,
To calculate the percentage increase in the rate, we use the equation:
Putting values in above equation, we get:
The above calculations proves that the rate of diffusion of is 0.4 % faster than the rate of diffusion of
According to Clausius-Clayperon equation,
is the vapor pressure at boiling point = 760 torr
is the vapor pressure at T_{2} =638.43 torr
Temperature
Δ
Plugging in the values, we get
ln
Therefore, the boiling point of octane = 389 K - 273 =