Answer:
Absolute pressure=70.72 KPa
Explanation:
Given that Vacuum gauge pressure= 30 KPa
Barometer reading =755 mm Hg
We know that barometer always reads atmospheric pressure at given situation.So atmospheric pressure is equal to 755 mm Hg.
We know that P= ρ g h
Density of ![Hg=13600 \frac{kg}{m^3}](https://tex.z-dn.net/?f=Hg%3D13600%20%5Cfrac%7Bkg%7D%7Bm%5E3%7D)
So P=13600 x 9.81 x 0.755
P=100.72 KPa
We know that
Absolute pressure=atmospheric pressure + gauge pressure
But here given that 30 KPa is a Vacuum pressure ,so we will take it as negative.
Absolute pressure=atmospheric pressure + gauge pressure
Absolute pressure=100.72 - 30 KPa
So
Absolute pressure=70.72 KPa
Answer:
True
Explanation:
Mass burn technology is a type of waste-to-energy technology commonly used in the mass-burn system, where unprocessed municipal solid waste is burned in a large incinerator with a boiler, to generate heat used in the production of electricity.
Answer:
1) ![V_o = 10 liters](https://tex.z-dn.net/?f=V_o%20%3D%2010%20liters)
2) ![V_o = 12.26 liters](https://tex.z-dn.net/?f=V_o%20%3D%2012.26%20liters)
Explanation:
For isothermal process n =1
![V_o =\frac{\Delta V}{(\frac{p_o}{p_1})^{1/n} -(\frac{p_o}{p_2})^{1/n}}](https://tex.z-dn.net/?f=V_o%20%3D%5Cfrac%7B%5CDelta%20V%7D%7B%28%5Cfrac%7Bp_o%7D%7Bp_1%7D%29%5E%7B1%2Fn%7D%20-%28%5Cfrac%7Bp_o%7D%7Bp_2%7D%29%5E%7B1%2Fn%7D%7D)
![V_o = \frac{5}{[\frac{72}{80}]^{1/1} -[\frac{72}{180}]^{1/1}}](https://tex.z-dn.net/?f=V_o%20%20%3D%20%5Cfrac%7B5%7D%7B%5B%5Cfrac%7B72%7D%7B80%7D%5D%5E%7B1%2F1%7D%20-%5B%5Cfrac%7B72%7D%7B180%7D%5D%5E%7B1%2F1%7D%7D)
![V_o = 10 liters](https://tex.z-dn.net/?f=V_o%20%3D%2010%20liters)
calculate pressure ratio to determine correction factor
![\frac{p_2}{p_1} =\frac{180}{80} = 2.25](https://tex.z-dn.net/?f=%5Cfrac%7Bp_2%7D%7Bp_1%7D%20%3D%5Cfrac%7B180%7D%7B80%7D%20%3D%202.25)
correction factor for calculate dpressure ration for isothermal process is
c1 = 1.03
![actual \ volume = c1\times 10 = 10.3 liters](https://tex.z-dn.net/?f=actual%20%5C%20volume%20%3D%20c1%5Ctimes%2010%20%3D%2010.3%20liters)
b) for adiabatic process
n =1.4
volume of hydraulic accumulator is given as
![V_o =\frac{\Delta V}{[\frac{p_o}{p_1}]^{1/n} -[\frac{p_o}{p_2}]^{1/n}}](https://tex.z-dn.net/?f=V_o%20%3D%5Cfrac%7B%5CDelta%20V%7D%7B%5B%5Cfrac%7Bp_o%7D%7Bp_1%7D%5D%5E%7B1%2Fn%7D%20-%5B%5Cfrac%7Bp_o%7D%7Bp_2%7D%5D%5E%7B1%2Fn%7D%7D)
![V_o = \frac{5}{[\frac{72}{80}]^{1/1.4} -[\frac{72}{180}]^{1/1.4}}](https://tex.z-dn.net/?f=V_o%20%20%3D%20%5Cfrac%7B5%7D%7B%5B%5Cfrac%7B72%7D%7B80%7D%5D%5E%7B1%2F1.4%7D%20-%5B%5Cfrac%7B72%7D%7B180%7D%5D%5E%7B1%2F1.4%7D%7D)
![V_o = 12.26 liters](https://tex.z-dn.net/?f=V_o%20%3D%2012.26%20liters)
calculate pressure ratio to determine correction factor
![\frac{p_2}{p_1} =\frac{180}{80} = 2.25](https://tex.z-dn.net/?f=%5Cfrac%7Bp_2%7D%7Bp_1%7D%20%3D%5Cfrac%7B180%7D%7B80%7D%20%3D%202.25)
correction factor for calculate dpressure ration for isothermal process is
c1 = 1.15
![actual \volume = c1\times 10 = 11.5 liters](https://tex.z-dn.net/?f=actual%20%5Cvolume%20%3D%20c1%5Ctimes%2010%20%3D%2011.5%20liters)