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lutik1710 [3]
3 years ago
5

What is a glass of iced tea containing excess sugar at the bottom said to be?

Chemistry
1 answer:
Pavel [41]3 years ago
5 0
The answer is saturated
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What is the chemical composition of hot chocolate?
iris [78.8K]

Answer:

Hot chocolate is as straightforward as drinks go: at its core, it's milk, cocoa powder, and sugar. Despite its simplicity, this cold-weather classic is swirling with science. The backbone of any decent hot chocolate is milk. Beyond water, milk is perhaps the most basic and familiar substance to humans.

7 0
2 years ago
Can anyone help me with this?
Scrat [10]

Explanation:

c2H5

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cH3 _ c _ c H2 _ c H3

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cH3

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5 0
2 years ago
Which of the following features is common to both acids and bases? A. ability to burn skin B. similar taste C. pH measurements g
Lynna [10]
<h3>Answer:</h3>

            Correct Option-A (Ability to burn skin)

<h3>Explanation:</h3>

                    When skin tissues are exposed to Acids or Bases a chemical burn occurs as both of these substances are corrosive in nature. These burns occur without providing any heat, results from a very fast reaction, are extremely painful and causes damage to structures present under skin.

                    Option-B is incorrect because Acids taste sour, while, Bases taste bitter.

                    Option-C is incorrect because pH of Acids is less than 7 while, pH of Bases is greater than 7.

3 0
3 years ago
Read 2 more answers
A 0.8870 g sample of a mixture of NaCl and KCl is dissolved in water, and the solution is then treated with an excess of AgNO3 t
bagirrra123 [75]

Answer : The percent by mass of NaCl and KCl are, 92.22 % and 7.78 % respectively.

Explanation :

As we know that when a mixture of NaCl and KCl react with excess AgNO_3 then the silver ion react with the chloride ion in both NaCl and KCl to form silver chloride.

Let the mass of NaCl be, 'x' grams and the mass of KCl will be, (0.8870 - x) grams.

The molar mass of NaCl and KCl are, 58.5 and 74.5 g/mole respectively.

First we have to calculate the moles of NaCl and KCl.

\text{Moles of }NaCl=\frac{\text{Mass of }NaCl}{\text{Molar mass of }NaCl}=\frac{xg}{58.5g/mole}=\frac{x}{58.5}moles

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{(0.8870-x)g}{74.5g/mole}=\frac{(0.8870-x)}{74.5}moles

As, each mole of NaCl and KCl gives one mole of chloride ions.

So, moles of chloride ions in NaCl = \frac{x}{58.5}moles

Moles of chloride ions in KCl = \frac{(0.8870-x)}{74.5}moles

The total moles of chloride ions = \frac{x}{58.5}moles+\frac{(0.8870-x)}{74.5}moles

Now we have to calculate the moles of AgCl.

As we know that, this amount of chloride ion is same as the amount chloride ion present in the AgCl precipitate. That means,

Moles of AgCl = Moles of chloride ion = \frac{x}{58.5}moles+\frac{(0.8870-x)}{74.5}moles

Now we have to calculate the moles of AgCl.

The molar mass of AgCl = 143.32 g/mole

\text{Moles of }AgCl=\frac{\text{Mass of }AgCl}{\text{Molar mass of }AgCl}=\frac{2.142g}{143.32g/mole}=0.0149moles

Now we have to determine the value of 'x'.

Moles of AgCl = \frac{x}{58.5}moles+\frac{(0.8870-x)}{74.5}moles

0.0149 mole = \frac{x}{58.5}moles+\frac{(0.8870-x)}{74.5}moles

By solving the term, we get the value of 'x'.

x=0.818g

The mass of NaCl = x = 0.818 g

The mass of KCl = (0.8870 - x) = 0.8870 - 0.818 = 0.069 g

Now we have to calculate the mass percent of NaCl and KCl.

\text{Mass percent of }NaCl=\frac{\text{Mass of }NaCl}{\text{Total mass of mixture}}\times 100=\frac{0.818g}{0.8870g}\times 100=92.22\%

\text{Mass percent of }KCl=\frac{\text{Mass of }KCl}{\text{Total mass of mixture}}\times 100=\frac{0.069g}{0.8870g}\times 100=7.78\%

Therefore, the percent by mass of NaCl and KCl are, 92.22 % and 7.78 % respectively.

3 0
3 years ago
What volume of 17.8 M stock sulfuric acid solution would be needed to make 2.0L of 0.200 M diluted sulfuric acid solution?
vodomira [7]

Answer:

Required Volume is 22.47ml

Explanation:

To make 2.0L of 0.2M sulfuric acid required moles = 0.2 x 2 = 0.4 moles

To get 0.4 from 17.8M required quantity = 1000/17.8 x 0.4 = 22.47ml

7 0
3 years ago
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