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mylen [45]
3 years ago
13

Considering factors that affect that solubility which statement below true?

Chemistry
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

Part A. The solubility of gases in water increases with increasing temperature.

Part B. Hexane (C₆H₁₄)

Explanation:

Part A

<em>Considering factors that affect that solubility which statement below true? </em>

  • <em>With a few exceptions, the solubility of most solid solutes in water decreases as the solution temperature increases.</em>  FALSE. With a few exceptions, the solubility of most solid solutes in water increases as the solution temperature increases.
  • <em>The solubility of gases in water increases with increasing temperature. </em> FALSE. In general, the solubility of gases decreases with increasing temperature.
  • <em>The solubility of a gas in any solvent is increased as the partial pressure of the gas above the solvent Increases. </em> TRUE. According to Henry's law, the solubility of a gas in a liquid is proportional to its partial pressure.
  • <em>Substances with similar intermolecular attractive forces tend to be insoluble in one another.</em> FALSE. Substances with similar intermolecular attractive forces tend to be soluble in one another.

Part B

<em> Which of these is the best solvent for nonpolar solutes? </em>

<em>acetone (CH₃COCH₃) </em>

<em>ethanol (CH₃CH₂OH) </em>

<em>hexane (C₆H₁₄) </em>

<em>water</em>

There is a general rule that states "like dissolves like", meaning polar is soluble in polar and nonpolar is soluble in nonpolar. Thus, hexane, which is the least polar solvent, would be the best choice for nonpolar solutes.

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LekaFEV [45]

Answer:

1.29 * 10^{24} particles of gold

Explanation:

To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always 6.022 × 10^{23}

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d

Explanation:

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6 0
4 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
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Answer:

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Explanation:

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∴ S°mH2O(l) = 69.9 J/mol.K

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3 years ago
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