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creativ13 [48]
4 years ago
12

Plzzzzzzzzzzzzzzzzzzz help me in these 3 questions plzzzzzzzzzzzzzzzzz ASAP!!

Physics
1 answer:
lana [24]4 years ago
3 0
A infared light has a higher
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PLEASE HELP. GRAVITY QUESTION, WRITTEN RESPONSE.
Rina8888 [55]

1) Forces acting on your body: force of gravity and normal reaction

2) Due to Newton's second law, N = mg

Explanation:

1)

When you sit on the computer, there are only two forces acting on you:

  • The force of gravity, acting downward, of magnitude W=mg, where m is your mass and g=9.8 m/s^2 is the acceleration due to gravity, downward
  • The normal reaction exerted by the chair on you, N, acting upward

Your body is in equilibrium (it doesn't move), this means that the two forces balance each other, therefore:

N-mg=0\\N=mg

2)

We can now apply Newton's second law of motion to this situation; this law states that the net force acting on a body is equal to the product between its mass and its acceleration. Mathematically,

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

In this situation, the net force is

\sum F = N-mg

So the equation becomes

N-mg=ma

However, we observe that your body is at rest; therefore, the acceleration is zero:

a = 0

And therefore,

N-mg=0\\N=mg

Learn more about forces:

brainly.com/question/8459017

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PLEASE HELP - Your concept map will compare the manner in which energy is transferred by mechanical waves and electromagnetic wa
makkiz [27]
The concept map is given in the attachment:

3 0
3 years ago
Read 2 more answers
One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6
ruslelena [56]
The electrostatic force between two charged objects is given by
F=k \frac{q_1 q_2}{r^2}
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:
q_1=+5.0 \cdot 10^{-6} C
q_2 = +2.0 \cdot 10^{-6} C
r=0.5 m
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(5.0 \cdot 10^{-6} C)(2.0 \cdot 10^{-6}C)}{(0.5 m)^2}=0.36 N
4 0
3 years ago
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