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3 years ago

The Duquenois-Levine Test is used when which drug is suspected?

Physics

2 answers:

NikAS [45]3 years ago

7 0

Weed my boy/girl it was 420
aka marajuna

Kaylis [27]3 years ago

6 0

Weed...its a marijuana test

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A 0.208 kg particle with an initial velocity of 1.26 m/s is accelerated by a constant force of 0.766 N over a distance of 0.195

eduard

Answer:

Explanation:

Initial kinetic energy of particle

= 1/2 m V²

= .5 x .208 x 1.26²

= .165 J

Work done by force = force x displacement

= .766 x .195

= .149 J

This energy will be added up .

Total final kinetic energy

= initial kinetic energy + work done on the particle

= .165 + .149 J

= .314 J .

3 0

3 years ago

The diagram below represents an electromagnetic wave. Please Help<br>

forsale [732]

Answer:

I'm pretty sure it's A

Explanation:

bc the crest is is the point on the wave

8 0

3 years ago

A 1.0 kg mass is attached to the end of a vertical ideal spring with a force constant of 400 N/m. The mass is set in simple harm

Marina86 [1]

Answer:

$v(0)=2m/s$

Explanation:

The instantaneous velocity of a point mass that executes a simple harmonic movement is given by:

$v(t)=\omega *A*cos(\omega t + \phi)$

Where:

$\omega=Angular\hspace{3}frequency\\A=Amplitude\\\phi=Initial\hspace{3}phase$

Express the amplitude in meters:

$10cm*\frac{1m}{100cm} =0.1m$

The angular frequency can be found using the next equation:

$\omega=\sqrt{\frac{k}{m} }$

Using the data provided:

$\omega=\sqrt{\frac{400}{1} } =20$

At the equilibrium position:

$\phi=0$

$v(0)=20*(0.1)cos(20*0+0)=2*cos(0)=2*1=2m/s$

6 0

3 years ago

You have been asked to make a roller coaster more exciting. The owners want the speed at the bottom of the first hill doubled. H

qaws [65]

Answer:

The height will be 4 times.

Explanation:

Given that,

The speed at the bottom of the hill doubled.

We need to calculate the height

Using conservation of energy

$K.E_{t}+P.E_{t}=K.E_{b}+P.E_{b}$

$K.E_{b}=P.E_{t}$

$\dfrac{1}{2}mv^2=mgh$

$\dfrac{1}{2}m(4v^2)=mgh$

Therefore,

$P.E = mg(4h)$

Here, m and g are constant

Hence, The height will be 4 times.

4 0

3 years ago

What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b? A. –7 ab B. `-7 a/b ` C

algol13

Answer:

C. -12 ab

Explanation:

The restoring force on a spring is given by Hooke's law:

$F=-kx$

where

k is the spring constant

x is the stretched (or compressed) displacement of the spring

In this problem we have:

k = 4a

x = 3b

Substituting into the equation, we find:

$F=-(4a)(3b) = -12 ab$

And the negative sign means that the direction of the force (negative) is opposite to the direction of the displacement (positive).

3 0

3 years ago