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Bad White [126]
3 years ago
15

Which salt is produced when sulfuric acid and calcium hydroxide react completely?

Chemistry
2 answers:
AnnyKZ [126]3 years ago
3 0

Answer: Option (4) is the correct answer.

Explanation:

When sulfuric acid reacts with calcium hydroxide then it results in the formation of calcium sulfate and water.

The chemical reaction for the same will be as follows.

     H_{2}SO_{4} + Ca(OH)_{2} \rightarrow CaSO_{4} + 2H_{2}O

Thus, we can conclude that CaSO_{4} salt is produced when sulfuric acid and calcium hydroxide react completely.

andrezito [222]3 years ago
3 0
CaSO4 is produced <span>when sulfuric acid and calcium hydroxide react completely.</span>
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Find the mass of 3.60x10^24 atoms of magnesium?
Arturiano [62]

Answer:

The answer to your question is 8.75 x 10 ²⁵ atoms of Magnesium

Explanation:

Data

Atomic mass of Magnesium = 24.31 g

Atoms of magnesium = 3.60 x 10²⁴

Process

Solve this porblem using a rule of three

             

           1 atom of Magnesium ---------------  24.31 g

           3.60 x 10²⁴                  ----------------    x

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3 0
4 years ago
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr
jenyasd209 [6]

Answer : The final temperature of the water is, 22.5166^oC

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives \frac{6542 kJ}{2}\times 0.1103=360.7913kJ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})

where,

q_w = heat released = 360.7913 kJ = 36079.13 J

m_w = mass of water = 5691 g

c_w = specific heat of water= 4.18J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 21^oC

Now put all the given values in the above formula, we get:

36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)

T_{final}=22.5166^oC

Therefore, the final temperature of the water is, 22.5166^oC

8 0
4 years ago
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