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3 years ago

A magnet is passed back and forth through a coil connected to a light bulb. The light bulb lights up. Why?

Physics

2 answers:

Alenkasestr [34]3 years ago

7 0

Answer:

From Faraday's law of Induction: A changing magnetic field induces emf in the coil.

Explanation:

Faraday's law states that when a coil is run through a changing magnetic field or a magnet is passed back and forth through a coil, an emf is induced which produces electric current in the coil.

Changing magnetic flux induces electromotive force.

$e = - \frac{d\phi}{dt} = -\frac{dB A}{dt}$

When the magnet is passed back and forth, it causes a changing magnetic flux around the coil. This induces emf and the current flows which lights up the bulb connected to it.

sdas [7]3 years ago

6 0

The moving back and forth of the magnetic causes a changing magnetic field, which induces an Emf through the coils of the wire and so the bulb ligts up.

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Vector has a magnitude of 4.40 m and is directed east. Vector has a magnitude of 3.40 m and is directed 39.0° west of north. Wha

Olenka [21]

Answer:

Magnitude = 4.056 m

Direction = 42.3⁰

Explanation:

The vector is resolved in terms of the vertical and horizontal components. Let's look each of these separately.

The vector 4.40 is directed East. This automatically becomes a horizontal component.

But we know that there is a vector 3.40 North West. The angle the vector makes with the horizontal is 61⁰.

Resolving the vectors should yield the horizontal and vertical components:

Horizontal components

The first component is 4.40 m

The second one is derived by resolving 3.40 to the horizontal like this 3.40 × - cos 61⁰ = -1.648 m

Adding the horizontal component gives 4.40 m + ( -1.648 m) = 2.752 m

Vertical components

Resolve 3.40 with the angle 61⁰ like this: vertical comp = 3.41 × sin 61

= 2.98 m

The magnitude is given by √[(2.98)²+ (2.752)²] = 4.056 m Ans

The direction us given by tan⁻¹ (2.98/2.752) = 42.3⁰ Ans

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3 years ago

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

Tju [1.3M]

Answer:

675m

Explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 6m/s²

Time = 15s

Unknown:

Distance traveled by the body = ?

Solution:

To solve this problem; we use the expression;

S = ut + $\frac{1}{2}$ at²

Where u is the initial velocity

t is the time

a is the temperature

Insert the parameters and solve;

S = 0 x 15 + $\frac{1}{2}$ x 6 x 15²

S = 675m

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Answer:

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a = 2.5 m/s/s

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