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timofeeve [1]
3 years ago
15

What parts of microscope that enlarge the object once seen under the microscope

Chemistry
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

lens are the answers, I hope it is right

Kobotan [32]3 years ago
4 0
I would think lens!
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A 35.0 ml sample of 0.225 m hbr was titrated with 42.3 ml of koh. What is the concentration of the koh?
Lemur [1.5K]

Answer:

The concentration of KOH is 0.186 M

Explanation:

First things first, we need too write out the balanced equation between HBr and KOH.

This is given as;

KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)

From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.

We use the acid base formular in calculating unknown concentrations. This is given as;

\frac{CaVa}{CbVb}  = \frac{na}{nb}

where;

Ca = Concentration of acid

Va = Volume of acid

Cb = Concentration of base

Vb = Volume of base

na = Number of moles of acid

nb = Number of moles of base

KOH is the base and HBr is acid.

Hence;

Ca = 0.225

Va = 35

Cb = ?

Vb = 42.3

na = 1

nb = 1

Making Cb subject of formular we have;

Cb = \frac{CaVaNb}{VbNa}

Cb = (0.225 * 35 * 1) / (42.3 * 1)

Cb = 0.186 M

5 0
3 years ago
Use the graph to answer both parts of this question about these three minerals. Do not use calculations.
11111nata11111 [884]

Answer:

Mercury is the most dense whereas Titanium is the least dense.

Explanation:

Since Density = Mass / Volume, the slope of the line can immediately tell us its relative density between the metals.

6 0
3 years ago
Read 2 more answers
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
Read 2 more answers
sorry that answer is wrong. A chemical bond is the force that holds together the elements in a compound
olya-2409 [2.1K]
That is a true statement <span />
8 0
3 years ago
The ending of a compounds name that is made up of three elements,one of which is oxygen​
Nezavi [6.7K]

Answer:

—COOH

Explanation:

—COOH, acid group, containing 3 elements, C, carbon, O, oxygen, and H, hydrogen.

7 0
3 years ago
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