b. A string is wrapped around a pulley of radius 0.05 m and moment of inertia 0.2 kg m2. If the string is pulled with a force
F, the resulting angular acceleration of the pulley is 2 rad/s2. Determine the magnitude of the force F.
1 answer:
Answer:
f = 8 N
Explanation:
Data provided in the question
Radius of the pulley = r = 0.05 m
Moment of inertia = (I) = 0.2 kg.m^{2}
Angular acceleration = ∝ = 2 rad/sec
Based on the above information
As we know that
Torque is


And,
Torque is also


So,
We can say that


0.05f = 0.4
f = 8 N
We simply applied the above formulas
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