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Evgen [1.6K]
3 years ago
13

fired, the ball moves 15.9 cm through the horizontal barrel of the cannon, and the barrel exerts a constant friction force of 0.

032 8 N on the ball. (a) With what speed does the projectile leave the barrel of the cannon
Physics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

Explanation:

Where is the remaining part of the question? This is a very easy one

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What is kinematics...? anyone on?​
mariarad [96]

Answer:

Kinematics is the motion of objects without reference of forces that causes the motion in objects.

Explanation:

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2 years ago
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Amy walks 3 m from her desk to the teacher's desk. From the teacher's desk, she then walks 4 m in the opposite direction to the
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Do you have pictures of the tables?
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3 years ago
Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
Tema [17]

Answer:

The value of developed electric force is 3.516\times 10^{- 7} N

Solution:

As per the question:

Mass of the droplet = 1.8 mg = 1.8\times 10^{- 6} kg

Charge on droplet, Q = 25 pC = 25\times 10^{- 12} C

Distance between the 2 droplets, D = 0.40 cm = 0.004 m

Now, the Electrostatic force given by Coulomb:

F_{E} = \frac{1}{4\pi epsilon_{o}}.\frac{Q^{2}}{D^{2}}

\frac{1}{4\pi epsilon_{o}} = 9\times 10^{9} m/F

F_{E} = (9\times 10^{9}).\frac{(25\times 10^{- 12})^{2}}{0.004^{2}}

F_{E} = 3.516\times 10^{- 7} N

The magnitude of force is too low to be noticed.

8 0
3 years ago
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12. A 0.5 kg ball traveling at 6.2 m/s collides head-on with a 1.0 kg ball traveling in the
Levart [38]

The final speed of the 1.0 kg ball is 1.9 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where we have:

m_1 = 0.5 kg is the mass of the first ball

u_1 = 6.2 m/s is the initial velocity of the first ball (taking its direction as positive direction)

v_1 = -14.0 m/s is the final velocity of the first ball (in the opposite direction)

m_2 = 1.0 kg is the mass of the second ball

u_2 = -12.0 is the initial velocity of the second ball

v_2 is the final velocity of the second ball

By re-arranging the equation and by substituting the values, we find: the final velocity of the second ball:

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(0.5)(6.2)+(1.0)(-12.0)-(0.5)(-14.0)}{1.0}=-1.9 m/s

And since the sign is negative, it means that the second ball travels in the same direction it was initially travelling.

Its speed is therefore (magnitude of the velocity) 1.9 m/s.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

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#LearnwithBrainly

7 0
3 years ago
I just need to reassurance, would they both be negative?
kirill [66]

Answer:

yep

Explanation:

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2 years ago
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