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balu736 [363]
3 years ago
5

5. What is required to cause acceleration? SN->

Chemistry
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

Change in Velocity

Explanation:

Acceleration will occur anytime an objects speed and time increases ri decreases.

exis [7]3 years ago
5 0

Answer:

The law states that unbalanced forces cause objects to accelerate with an acceleration that is directly proportional to the net force and inversely proportional to the mass. Acceleration is caused both by magnitude and direction of velocity.

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What Li(s) + O2(g) -> Li2O(s) balanced is
Ivahew [28]

Answer:

<h2>4 1 2</h2>

Explanation:

4 Li(s) + 1 O2(g) -> 2 Li2O(s)

3 0
3 years ago
Which is the anode (oxidation) and cathode (reduction)?
arsen [322]

Answer:

2H+ + 2e - ---> H2(g) is the cathode

2Cl - ---> Cl2(g) + 2e - is the anode

Explanation:

Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.

8 0
3 years ago
Why did acid make our teeth rot?
kotykmax [81]

Explanation:

acid make our teeth rot because strong acid are corrosive

8 0
3 years ago
Read 2 more answers
What is the molecular formula of a compound with the empirical formula HSO4 and a formula mass of 194.13 amu?
nadya68 [22]

Answer:

Molecular formula =  H₂S₂O₈

Explanation:

Given data:

Empirical formula = HSO₄

Formula mass = 194.13 amu

Molecular mass = ?

Solution:

Molecular formula = n × empirical formula

n = molar mass of the compound / empirical formula mass

Empirical formula mass = 1.008 + 32.065 + 16× 4

Empirical formula mass = 97.073

n = 194.13 / 97.073

n= 2

Molecular formula = n × empirical formula

Molecular formula = 2  (HSO₄)

Molecular formula =  H₂S₂O₈

4 0
4 years ago
Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

r = \dfrac{a}{2\sqrt{2}}

where;

a = edge length.

Making "a" the subject of the formula:

a = 2 \sqrt{2} \times r

a = 2 \times 1.414 \times 135 \ pm

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

mass of unit cell = 6.83380375 × 10⁻²² g

Density  \ of  \ unit \  cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}

Density of unit cell ( rhodium) = 12.279 g/cm³

3 0
3 years ago
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