Explanation:
One of the takeaways of the General Theory of Relativity (GTR) was that the light can be curved because of the gravity of a massive object. Einstein had proposed the idea of <em>space-time</em> fabric. Every object having mass will create depression in this fabric. Heavier the object, bigger the depression. Thus when light will pass near a heavy object lets say our Sun, it will deflect. He also gave mathematical formula to calculate the deflection.
The same was proved during the Total Solar Eclipse of 29 May 1919. Two scientists named Arthur Eddington and Frank Dyson conducted an experiment. In this eclipse the Sun was to be in front of Hyades in Taurus constellation. They took the measurement of stars of Hyades visible during the eclipse and then compared them with the actual readings. The deflection was clearly visible and the amount of deflection was very close to the values predicted by General Theory of Relativity. Thus they proved the theory right.
Answer:
It makes it lighter when its closer and heavier when its farther way.
Explanation:
Answer:
Hey ! I think I can help with this question.
In the diagram you were given the speed which is 5.25m/s and you were also given distance which is 950metres.
So the formula which will be suitable in my own way will be speed=distance/time....Since you weren't given the time,then you can place the numbers in their respectively places which will be 5.25=950/time....Then you will cross multiply which will be 5.25t=950....Then 950÷5.25=180.952381 which is approximately 181. then don't forget to add your unit, time is measured in seconds so the answer is going to be 181seconds.This is what I know...I hope this helps you.....Thank you for the question
Answer:
(a)
(b) Kinetic Energy of planet with mass m₁, is KE₁ = 1.068×10³² J
Kinetic Energy of planet with mass m₂, KE₂ = 2.6696×10³¹ J
Explanation:
Here we have when their distance is d apart
Energy is given by
Conservation of linear momentum gives
m₁·v₁ = m₂·v₂
From which
v₂ = m₁·v₁/m₂
At equilibrium, we have;
which gives
multiplying both sides by m₂/m₁, we have
Such that v₁ =
Similarly, with v₁ = m₂·v₂/m₁, we have
From which we have;
and
The relative velocity = v₁ + v₂ =
v₁ + v₂ =
(b) The kinetic energy KE =
Just before they collide, d = r₁ + r₂ = 3×10⁶+5×10⁶ = 8×10⁶ m
= 10333.696 m/s
=2583.424 m/s
KE₁ = 0.5×2.0×10²⁴× 10333.696² = 1.068×10³² J
KE₂ = 0.5×8.0×10²⁴× 2583.424² = 2.6696×10³¹ J.
The correct answer is
B. Interference