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Aleks [24]
3 years ago
11

At exactly the same time, Daisy and Damond both step off a diving platform 5 meters high. Damond jumps up and out from the platf

orm, whereas Daisy just just takes a step from a standing position.
Which of the following is true?
A. The person who has less mass will reach the water first.
B. Daisy will reach the water first.
C. Damon will reach the water first.
D. Damond and Daisy will reach the water at the same time.
Physics
1 answer:
Tom [10]3 years ago
4 0

Answer:

B

Explanation:

A. False.  Their mass does not affect when they reach the water.

B. True.  Daisy will reach the water in 1 second.

C. False.  Damon will reach the water in more than 1 second.

D. False.  Daisy reaches the water first.

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Why is it important to know the location of active and inactive faults in our country?
Andrew [12]

Answer:

I hope this helps.

Explanation:

It's important to know the location of an active fault in order to determine the magnitude of the expected earthquake. There is a chance than an inactive fault can become active again. It's important that we take the locations into account in order to be prepared and ready for if it occurs.

5 0
3 years ago
A girl of mass m1=60 kilograms springs from a trampoline with an initial upward velocity of v1=8.0 meters per second. At height
AleksandrR [38]

a) 5.0 m/s

This first part of the problem can be solved by using the conservation of energy. In fact, the mechanical energy of the girl just after she jumps is equal to her kinetic energy:

E_i=\frac{1}{2}m_1v_1^2

where m1 = 60 kg is the girl's mass and v1 = 8.0 m/s is her initial velocity.

When she reaches the height of h = 2.0 m, her mechanical energy is sum of kinetic energy and potential energy:

E_f = \frac{1}{2}m_1 v_2 ^2 + m_1 gh

where v2 is the new speed of the girl (before grabbing the box), and h = 2.0m. Equalizing the two equations (because the mechanical energy is conserved), we find

\frac{1}{2}m_1 v_1^2 = \frac{1}{2}m_1 v_2 ^2 + m_1 gh\\v_1^2 = v_2^2 +2gh\\v_2 = \sqrt{v_1^2 -2gh}=\sqrt{(8.0 m/s)^2-(2)(9.8 m/s^2)(2.0 m)}=5.0 m/s

b) 4.0 m/s

After the girl grab the box, the total momentum of the system must be conserved. This means that the initial momentum of the girl must be equal to the total momentum of the girl+box after the girl catches the box:

p_i = p_f\\m_1 v_2 = (m_1 + m_2) v_3

where m2 = 15 kg is the mass of the box. Solving the equation for v3, the combined velocity of the girl+box, we find

v_3 = \frac{m_1 v_2}{m_1 + m_2}=\frac{(60 kg)(5.0 m/s)}{60 kg+15 kg}=4 m/s

c) 2.8 m

We can use again the law of conservation of energy. The total mechanical energy of the girl after she catches the box is sum of kinetic energy and potential energy:

E_i = \frac{1}{2}(m_1+m_2) v_3^2 + (m_1+m_2)gh=\frac{1}{2}(75 kg)(4 m/s)^2+(75 kg)(9.8 m/s^2)(2.0m)=2070 J

While at the maximum height, the speed is zero, so all the mechanical energy is just potential energy:

E_f = (m_1 +m_2)gh_{max}

where h_max is the maximum height. Equalizing the two expressions (because the mechanical energy must be conserved) and solving for h_max, we find

E_i = (m_1+m_2)gh_{max}\\h_{max}=\frac{E_i}{(m_1+m_2)g}=\frac{2070 J}{(75 kg)(9.8 m/s^2)}=2.8 m

4 0
3 years ago
Help asapp!!!!!!!!!!!!!!
IRINA_888 [86]
Sorry don’t know this one
3 0
3 years ago
Sound will travel slowest through which medium?
xxMikexx [17]
Ice at -25
Hope this helps
May God bless you and your family
8 0
3 years ago
As you read this in your chair, how fast are you moving relative to the chair? relative to the sun?
Oliga [24]
To answer this question, you need to know the definition of Relative Motion:
 The motion is relative when it depends on a reference point or referencial system. If you know the reference point, you can determine the velocity of an object.
 If you are sitting on your chair, you are not moving relative to it (Your speed is 0 km/s); but as you know, our planet moves around the Sun (Traslation Movement) with a speed of 30.0 km/s. Therefore, you are moving 30.0 km/s relative to the sun.
5 0
3 years ago
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