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3 years ago

5

How is shielding effect related to atomic radius?

1 answer:

jolli1 [7]3 years ago

7 0

Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius

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To make an object start moving, you must exert a force in

BaLLatris [955]

Answer: c any

Explanation:

3 0

3 years ago

What class of organic product results when 1-heptyne is treated with a mixture of mercuric acetate (HgSO4) in aqueous sulfuric a

Alekssandra [29.7K]

Answer:

<u>heptan-2-one</u>

Explanation:

In this case, the final product would be a ketone: <u>heptan-2-one</u>. To understand why this molecule is produced we have to check the<u> reaction mechanism</u>.

The first step is the <u>protonation</u> of the triple bond to produce the more stable carbocation (a secondary one) by the action of sulfuric acid $H_2SO_4$ . The next step is the <u>attack of water</u> to the carbocation to produce a new bond between C and the O, producing a positive charge in the oxygen. Then, a <u>deprotonation</u> step takes place to produce an <u>enol</u>. Finally, we will have a rearrangement (<u>keto-enol tautomerism</u>) to produce the final ketone.

See figure 1

I hope it helps!

7 0

4 years ago

A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31

Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

$PV = nRT$

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

$n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles$

Now, we can find the temperature with the final conditions:

$T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K$

The temperature in Celsius is:

$T_{2} = 274.7 - 273 = 1.7 ^{\circ} C$

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!

8 0

3 years ago

Convert the density 2.32 g/mL to the unit kg/m3.

Annette [7]

(2.32g/cm³) x (1kg/1000g)x(1 000 000 cm³/1m³) = 2320 kg/m³

1 ml= 1 cm³

8 0

4 years ago

More dense substances will ...

REY [17]

Answer: B

Explanation:

The more dense an object is, the more it will sink below something. If the liquid below the more dense object is even denser, it is going to sink.

The light object will not be able to handle the heavy object. The answer to the question is option B.

4 0

3 years ago

Read 2 more answers