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Andreyy89
3 years ago
14

Ladybug walks 10 cm forward and 5 cm backwards in 20 seconds what is the average speed of ladybug what is the average velocity

Physics
2 answers:
Tamiku [17]3 years ago
4 0

Hey!

---------------------------------------------------

Formula: Distance / Time = Speed

---------------------------------------------------

Solution:

Speed = 15/20 = 0.75cm/sec

Velocity = 5/20 = 0.25cm/sec

10 + 5 = 15 (distance traveled)

---------------------------------------------------

Answer:

Speed = 0.75cm/sec

Velocity = 0.25cm/sec going forward.

---------------------------------------------------

Hope This Helped! Good Luck!

lbvjy [14]3 years ago
3 0

Answer:

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

Explanation:

Speed is the ratio of distance and time and velocity is the ratio of displacement and time.

Distance traveled = 10 + 5 = 15 cm = 0.15 m

Displacement = 10 - 5 = 5 cm = 0.05 m

Time = 20 seconds

\texttt{Average speed = }\frac{\texttt{Distance}}{\texttt{Time}}\\\\\texttt{Average speed = }\frac{0.15}{20}=7.5\times 10^{-3}m/s\\\\\texttt{Average velocity = }\frac{\texttt{Displacement}}{\texttt{Time}}\\\\\texttt{Average velocity = }\frac{0.05}{20}=2.5\times 10^{-3}m/s

Average speed = 0.0075 m/s

Average velocity = 0.0025 m/s along forward direction

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alisha [4.7K]

Answer:

B) 200 [J]

Explanation:

In order to solve this problem we must remember the definition of work which tells us that it is equal to the product of force by a distance, in this case, the force is the weight of the ball. The distance traveled is 4 [m] since 6-2 = 4[m]

F = m*g

where:

m = mass = 5 [kg]

g = gravity acceleration = 10 [m/s^2]

F = 5*10 = 50 [N]

w = F*d

where:

F = force = 50 [N]

d = 4 [m]

w = 50*4 = 200 [J]

4 0
3 years ago
A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.​
-BARSIC- [3]

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

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t is the time

From the question we have

a =  \frac{160}{4.5}  = 35.55555...

We have the final answer as

<h3>35.56 m/s²</h3>

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6 0
3 years ago
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So in this problem, the two vectors that will have the largest magnitude are A & F when subtracted (i.e., when one vector is subtracted from the other).

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