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algol [13]
3 years ago
9

The minimum waste compaction ratio reported by the manufacturer of a high-pressure compaction machine is 8:1. What is the corres

ponding percent volume reduction of the waste
Engineering
1 answer:
Crank3 years ago
6 0

Answer:

12.5%

Explanation:

Compaction ratio= Volume before reduction/volume after reduction

Compaction ratio= 8/1

% reduction in volume= Volume after reduction/Volume before reduction× 100= 1/compaction ratio × 100

% reduction in volume= 1/(8/1) × 100

                                    =12.5

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Why is it better for a CPU to have more than one cache?
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In general a cache memory is useful because the speed of the processor is higher than the speed of the ram . so reducing the number of memory is desirable to increase performance .

Explanation:

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2 years ago
Why is it important to know where your online information comes from?
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It is very important to know where online information comes from in order to validate, authenticate and be sure it's the right information

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5 0
2 years ago
What is the primary reason traffic laws exist ?
kramer

so people dont die whaddya think?

4 0
3 years ago
Read 2 more answers
Implement the function F(A, B, C, D) = Σm(1, 2, 3, 4, 6, 9, 12, 13, 15) as a minimal hazard-free SOP circuit. In your solution,
Marina86 [1]

Answer:

See attachment below

Explanation:

3 0
4 years ago
1. The equilibrium number of vacancies in Ni at 1123 K is 4.7x1022m-3. The atomic weight and density of Ni at 1123 K are 58.69 g
Ahat [919]

Answer:

vacancy formation energy of Ni is 1.400 eV

Explanation:

given data

number of vacancies in Ni = 4.7 x 10^{22}  m^{-3}

atomic weight = 58.69 g/mol

density = 8.8 g/cm³  

solution

we get here N that is

N  = \frac{N_A \times \rho}{A}   ...........1

N = \frac{6.023\times 10^{23} \times 8.8 \times 10^6}{58.69}

N = 9.030 \times 10^{28}  

and here no of vacancy will be

Nv = N \times e^{\frac{-Qv}{kT}}  .................2

put here value

4.7 \times 10^{22} = 9.030 \times 10^28 \times e^{\frac{-Qv}{8.62\times 10^{-5}\times 1123}}  

10^{-7} \times 5.20487 = e^{\frac{-Qv}{0.0968}}

take ln both side

ln (10^{-7} \times 5.20487 ) = ln (e^{\frac{-Qv}{0.0968}})

-14.468 = \frac{-Qv}{0.0968}  

Qv = 1.400 eV

so vacancy formation energy of Ni is 1.400 eV

3 0
3 years ago
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