Answer:
Explanation:
We shall apply Pascal's Law in fluid mechanics
According to it , pressure is transmitted in liquid from one point to another without any change .
25 cm diameter = 12.5 x 10⁻² m radius
Area = 3.14 x (12.5 x 10⁻²)²
= 490.625 x 10⁻⁴ m²
Pressure by vehicle
Force / area
13000 / 490.625 x 10⁻⁴
= 26.497 x 10⁴ Pa
5 cm diameter = 2.5 x 10⁻² radius
area = 3.14 x (2.5 x 10⁻²)²
= 19.625 x 10⁻⁴ m²
If we assume required force F on this area
Pressure = F / 19.625 x 10⁻⁴ Pa
According to Pascal Law
F / 19.625 x 10⁻⁴ = 26.497 x 10⁴
F = 19.625 x 26.497
= 520 N
For a 650-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth’s mean radius, the resultant values are is mathematically given as
- V=5.59*10^3m/s
- T=3.98hours
- F=1.47*10^3N
<h3>What are the satellite’s orbital speed, the period of its revolution, and the gravitational force acting on it.?</h3>
Generally, the equation for satellite orbital speed is mathematically given as
a)
V=5.59*10^3m/s
b)
T=3.98hours
c)
Therefore
F=1.47*10^3N
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Answer:
F = 0.414 N
Explanation:
Given that,
Magnetic flux density,
The length of the wire, l = 24 m
Current, I = 0.48 A
We need to find the force acting on the wire. The formula for the force is given by:
Put all the values,
So, the force acting on the copper wire is equal to 0.414 N.