1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hjlf
3 years ago
11

The secret recipe to the ever-popular veggie burgers in the college cafeteria is hidden in a drawer in the director’s office. Tw

o students decide to break in to get their hands on it, but they want to do it a few hours before dawn on a night when there is no Moon, so they are less likely to be caught. What phases of the Moon would suit their plans?
Physics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

Waxing crescent to Waxing gibbous

Explanation:

As the Moon goes around Earth and Earth goes around the Sun, the Moon shows us different phases throughout this journey. Also because of peculiar revolution period around the Earth the rise and set time of Moon changes daily. New Moon rises with the Sun rise and sets with Sun set. Waxing half rises in the mid of the day and sets at midnight. Full Moon rises after sunset and sets at sunrise.

The suitable phases will be from waxing crescent to waxing gibbous. The phase of the Moon, 3 days before the full Moon can be selected as the Moon will set by around 2.5 hours before the Sun rise.

You might be interested in
A 25.0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic frictio
Alekssandra [29.7K]

Answer:

The minimum angle at which the box starts to slip (rounded to the next whole number) is α=19°

Explanation:

In order to solve this problem we must start by drawing a sketch of the problem and its corresponding fre body diagram (See picture attached).

So, when we are talking about friction, there are two types of friction coefficients. Static and kinetic. Static friction happens when the box is not moving no matter what force you apply to it. You get to a certain force that is greater than the static friction and the box starts moving, it is then when the kinetic friction comes into play (kinetic friction is generally smaller than static friction). So in order to solve this problem, we must find an angle such that the static friction is the same as the force applie by gravity on the box. For it to be easier to analyze, we must incline the axis of coordinates, just as shown on the picture attached.

After doing an analysis of the free-body diagram, we can build our set of equations by using Newton's thrid law:

\sum F_{x}=0

we can see there are only two forces in x, which are the weight on x and the static friction, so:

-W_{x}+f_{s}=0

when solving for the static friction we get:

f_{s}=W_{x}

We know the weight is found by multiplying the mass by the acceleration of gravity, so:

W=mg

and:

W_{x}=mg sin \alpha

we can substitute this on our sum of forces equation:

f_{s}=mg sin \alpha

the static friction will depend on the normal force applied by the plane on the box, static friction is found by using the following equation:

f_{s}=N\mu_{s}

so we can substitute this on our equation:

N\mu_{s}=mg sin \alpha

but we don't know what the normal force is, so we need to find it by doing a sum of forces in y.

\sum F_{y}=0

In the y direction we got two forces as well, the normal force and the force due to gravity, so we get:

N-W_{y}=0

when solving for N we get:

N=W_{y}

When seeing the free-body diagram we can determine that:

W_{y}=mg cos \alpha

so we can substitute that in the sum of y-forces equation, so we get:

N=mg cos \alpha

we can go ahead and substitute this equation in the sum of forces in x equation so we get:

mg cos \alpha \mu_{s}=mg sin \alpha

we can divide both sides of the equation into mg so we get:

cos \alpha \mu_{s}=sin \alpha

as you may see, the angle doesn't depend on the mass of the box, only on the static coefficient of friction. When solving for \mu_{s} we get:

\mu_{s}=\frac{sin \alpha}{cos \alpha}

when simplifying this we get that:

\mu_{s}=tan \alpha

now we can solve for the angle so we get:

\alpha= tan^{-1}(\mu_{s})

and we can substitute the given value so we get:

\alpha= tan^{-1}(0.350)

which yields:

α=19.29°

which rounds to:

α=19°

8 0
3 years ago
When a driver hits the brakes, his car decelerates from 50m/s at a uniform rate of 2.0m/s^2. His car stops after covering some d
Assoli18 [71]

Please find attached photograph for your answer. Please do comment whether it is useful or not.

7 0
3 years ago
You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.00m/s, direc
erik [133]
The height of the balcony may be calculated through the equation,
                                h = V₀t + 0.5gt²
where h is the height, V₀ is the initial velocity, g is the gravitational constant and t is time. Substituting the values given above,
                               h = (5 m/s)(2s) + 0.5(10 m/s²)(2 s)²
                                 h  = 30 m
Thus, the height of the balcony is 30 meters. 
5 0
4 years ago
What is the minimum speed needed to fire a champagne cork a distance of 11m?
Crank

To start with solving this problem, let us assume a launch angle of 45 degrees since that gives out the maximum range for given initial speed. Also assuming that it was launched at ground level since no initial height was given. Using g = 9.8 m/s^2, the initial velocity is calculated using the formula:

(v sinθ)^2 = (v0 sinθ)^2 – 2 g d

where v is final velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m

Rearranging to find for v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>

<span>v0 = 10.383 m/s</span>

8 0
3 years ago
Which waves can travel through space?
xz_007 [3.2K]

Answer:

electromagnetic waves only

Explanation:

I just took the test, Hope it helps!

4 0
3 years ago
Read 2 more answers
Other questions:
  • The cardiovascular system consists of
    10·1 answer
  • What are some physical properties of a star
    14·2 answers
  • If an engine has a compression ratio of 7:1,
    7·2 answers
  • 6. If a car went a distance of 225 kilometers in 4
    7·1 answer
  • Democritus thought that matter was made of tiny particles. true or false
    14·2 answers
  • QUESTION 10
    11·1 answer
  • In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15
    15·1 answer
  • What law of motion does this picture represent?​
    6·2 answers
  • My teacher ask me to slove this question please help me.
    11·1 answer
  • A Hunter points his gun at a squirrel on a branch of a tree away from him. Assume he lies on the ground and that the moment he f
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!