Answer:
the formula is 164.088 g/mol
Explanation:
Haha i’m trying to do the same one i’ll make sure if i find out how too to get back to you!
Answer:
stars,auroras,a neon sign
Explanation:
just did it
Well, we need to find the ratio of Al to the other reactant.
Al:HCl = 1:3
--> this means that for every 1 Al used, you have to use 3 HCl.
6*3 = 18 moles of HCl needed to fully react with 6 moles of Al. Since 13<18, HCL is the limiting reactant.
The ratio of HCl:AlCl = 3:1
13/3 = 4.3333...
The final answer is HCl is the limiting reactant with 4.3 moles of AlCl3 able to be produced.
Hope this helps!!! :)
