1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
5

PLEASE NO LINKS OR FILE SCAMS

Chemistry
1 answer:
cluponka [151]3 years ago
7 0
The equation as written is already balanced.
You might be interested in
What element is chemically combined with hydrogen
Fudgin [204]

Uh I think water is??

5 0
2 years ago
Plz help me i swear will mark you brainiest :(
vladimir1956 [14]

Answer:

C. the relative molecular mass of the compound

Explanation:

Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.

7 0
2 years ago
A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )

V_{2} = 0.000151 m^{3}

This is the final volume of the sample of gas.

4 0
3 years ago
A 455 g piece of bopper tubing is heated to 89.5 C and placed in an insulated vessel containing 159 g of water at 22.8 C. Assumi
postnew [5]

Answer:

The final temperature of the setup = 36.6°C

Explanation:

Let the final temperature of the setup be T

Heat lost by the copper tubing = Heat gained by water and the vessel

Heat lost by the copper tubing = mC ΔT = 455 × 0.387 × (89.5 - T) = (15759.61 - 176.1T) J

Heat gained by water = mC ΔT = 159 × 4.186 × (T - 22.8) = (665.6T - 15175.1) J

Heat gained by vessel = c ΔT = 10 × (T - 22.8) = (10T - 228) J

Heat lost by the copper tubing = Heat gained by water and the vessel

(15759.61 - 176.1T) = (665.6T - 15175.1) + (10T - 228)

851.7 T = 31162.71

T = 36.6°C

7 0
2 years ago
2.5 * 10^4 gallons to mL
Gre4nikov [31]
(2.5)(10000)=25000

25000 * 3785

ML = 94635294.6 milliliters
6 0
3 years ago
Other questions:
  • Which is larger an atom or a molecule? Explain your answer.
    7·1 answer
  • What are the similarities between the adrenal hormone cortisone and the synthetic corticoid prednisone?
    6·1 answer
  • How many electrons does A1 3+​
    12·1 answer
  • Convert eachh into scientific notation
    13·2 answers
  • How can you experimentally determine the solubility of a solute in water at a certain temperature?
    6·1 answer
  • What similarities are there between Beta Radiation and Alpha Radiation
    6·1 answer
  • PLEASE SOMEONE HELP ME WITH THIIS QUESTION
    14·1 answer
  • How can you tell that the solution contains a weak acid?
    7·1 answer
  • What is NaHCO3 = Na2CO3 + H2O + CO2 as a balanced equation?
    11·1 answer
  • How to solve 20.0 mL/ 5.7 g with significant figures and including units
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!