All categories

2 years ago

Describe how mass affects the time required for an object to reach the ground from a given drop height.

1 answer:

6 0

The speed of a falling object is not directly affected by mass. Air resistance is the deciding factor in the time is takes for an object to reach the ground. Two objects of different mass will accelerate at the same rate. This was discovered by Galileo. Newton's second law states that F=ma. This means that if both accelerate at the same rate, then the force acting on the objects must be different, and the greater the mass, the greater the force of gravity that is acting upon the object.

You might be interested in

A fire breaks out and increases the Kelvin temperature of a cylinder of compressed gas by a factor of 2.4. What is the final pre

kherson [118]

Answer:

P(final) is 2.4 times P(initial).

Explanation:

Here we can assume that the cylinder did not break and it's volume and number of moles of gas present in the cylinder remains constant.

Given the temperature increases by a factor of 2.4. Let us assume that the initial temperature be $T_{1}$ and the final temperature be $T_{2}$ .

Given that $T_{2}=2.4\times T_{1}$

Now we know the ideal gas equation is PV=nRT

here V=constant , n=constant , R=gas constant(which is constant).

$\frac{P}{T}=constant$

$\frac{P_{1} }{T_{1}}=\frac{P_{2} }{T_{2} }$

$P_{2}=(\frac{T_{2} }{T_{1} } )P_{1}$

$P_{2}=(\frac{2.4T_{1} }{T_{1} } )P_{1}$

$P_{2}=2.4\times P_{1}$

7 0

2 years ago

3. Question

aalyn [17]

2. Newton's laws of motion

5 0

3 years ago

Read 2 more answers

A 900 N student runs up the stairs 3.5 m high in 12 seconds. How much POWER do they generate?

never [62]

Answer:

Ur litterly dog water ✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

4 0

2 years ago

2. A student places an object with a mass of m on a disk at a position r from the center of the disk. The student starts rotatin

ycow [4]

Answer:

$\frac{0.065}{r}$

Explanation:

The maximum velocity of an object moving in a curve beyond which it will slide off the curve is given by the relationship in equation (1);

$v=\sqrt{\mu gr}....................(1)$

where $\mu$ is the coefficient of friction between the object and the surface of the curve, g is acceleration due to gravity and r is the radius of the curve.

Given;

v = 0.8m/s

g = $9.81m/s^2$

r = ?

$\mu=?$

In order to solve for $\mu$ , we can simply make it the subject of formula from equation (1) as follows;

$v^2=\mu gr\\hence\\\mu=\frac{v^2}{gr}.................(2)$

since we were not given the value of r, we can just substitute other known values, then solve and leave the answer in terms of r.

Therefore;

$\mu=\frac{0.8^2}{9.81r}$

$\mu=\frac{0.64}{9.81r}\\\\\mu=\frac{0.065}{r}$

8 0

3 years ago

I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?

Ulleksa [173]

Answer:

B. 68.6m

Explanation:

Free Fall Motion

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

$\displaystyle y=\frac{gt^2}{2}$

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

$\displaystyle y=\frac{(9.8)(3.474)^2}{2}$

$\displaystyle y=68.54\ m$

The closest correct option is

B. 68.6m

5 0

3 years ago