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Gwar [14]
3 years ago
12

Describe how mass affects the time required for an object to reach the ground from a given drop height.

Physics
1 answer:
lys-0071 [83]3 years ago
6 0
The speed of a falling object is not directly affected by mass. Air resistance is the deciding factor in the time is takes for an object to reach the ground. Two objects of different mass will accelerate at the same rate. This was discovered by Galileo. Newton's second law states that F=ma. This means that if both accelerate at the same rate, then the force acting on the objects must be different, and the greater the mass, the greater the force of gravity that is acting upon the object. 
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If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain u
zaharov [31]

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

6 0
3 years ago
Read 2 more answers
what is the amplitude and wavelength of the wave shown below? A. Amplitude: 15 cm; wavelength: 150 cm B. Amplitude: 30 cm; wavel
ehidna [41]
I would say C...............
5 0
3 years ago
Read 2 more answers
10) Two students want to use a 12-meter long rope to create standing waves. They first measure the speed at which a single wave
zhannawk [14.2K]

Answer:

To create a second harmonic the rope must vibrate at the frequency of 3 Hz

Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

f₁ = v/2L

where,

v = speed of wave = 36 m/s

L = Length of rope = 12 m

f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

where,

fn = frequency of nth harmonic

n = No. of Harmonic = 2

f₁ = fundamental frequency = 1.5 Hz

Therefore,

f₂ = (2)(1.5 Hz)

<u>f₂ = 3 Hz</u>

5 0
3 years ago
Use the equation d = m/v [stack fraction), where d= density, m= mass, and v
sladkih [1.3K]

Answer:

54.

Explanation:

6 (v) x 9 (m) = 54.

54 (m) / 6 (v) = 9 (d)

5 0
3 years ago
A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1
ss7ja [257]

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

5 0
2 years ago
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