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Gwar [14]
3 years ago
12

Describe how mass affects the time required for an object to reach the ground from a given drop height.

Physics
1 answer:
lys-0071 [83]3 years ago
6 0
The speed of a falling object is not directly affected by mass. Air resistance is the deciding factor in the time is takes for an object to reach the ground. Two objects of different mass will accelerate at the same rate. This was discovered by Galileo. Newton's second law states that F=ma. This means that if both accelerate at the same rate, then the force acting on the objects must be different, and the greater the mass, the greater the force of gravity that is acting upon the object. 
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At time t = 0 s, an object is observed at x = 0 m; and its position along the x-axis follows this expression: x = –4t + t2, wher
Anit [1.1K]

Answer:

The object displacement is 0 meters.

Explanation:

Because the expression for the object position as function of time is:

x(t)= -4t + t^2

At t= 3.0=t2 seconds the x-position of the object is:

x(3.0)= -4(3.0) + (3.0)^2

x(3.0s)=-3 m

and at t=1.0=t1 seconds the x-position of the objects is:

x(1.0)= -4(1.0) + (1.0)^2

x(1.0s)=-3m

The total displacement (\Delta x) of the object between t2 and t1 is the difference between x(3.0s) and x(1.0s):

\Delta x= x(3.0)-x(1.0)=-3.0-(-3.0)

\Delta x=0m

The displacement of the object is zero!!!

5 0
3 years ago
The electric field in a region is uniform (constant in space) and given by E-( 148.0 1 -110.03)N/C. An additional charge 10.4 nC
enyata [817]

Answer:

The y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

Explanation:

<u>Given:</u>

  • Electric field in the region, \vec E = (148.0\ \hat i-110.0\ \hat j)\ N/C.
  • Charge placed into the region, q = 10.4\ nC = 10.4\times 10^{-9}\ C.

where, \hat i,\ \hat j are the unit vectors along the positive x and y axes respectively.

The electric field at a point is defined as the electrostatic force experienced per unit positive test charge, placed at that point, such that,

\vec E = \dfrac{\vec F}{q}\\\therefore \vec F = q\vec E\\=(10.4\times 10^{-9})\times (148.0\ \hat i-110.0\ \hat j)\\=(1.539\times 10^{-6}\ \hat i-1.144\times 10^{-6}\ \hat j)\ N.

Thus, the y-component of the electric force on this charge is F_y = -1.144\times 10^{-6}\ N.

3 0
3 years ago
Giving brainlist so plz help
Volgvan

Answer:

I DON KNOW

Explanation:

6 0
4 years ago
Which fundamental force is very strong across a short distance?
lesya692 [45]

B. Strong nuclear

Because the strong nuclear force is the strongest at short distances, it dominates over the other forces and the two protons become bound, forming a helium nucleus (typically a neutron is also needed to keep the helium nucleus stable).

5 0
3 years ago
Read 2 more answers
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
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