2 years ago

What happens when a negatively charged object A is brought near a neutral object B?

Physics

2 answers:

Andrews [41]2 years ago

6 0

Object B gets a positive charge

Eva8 [605]2 years ago

5 0

<span>Object B stays neutral but becomes polarized.

Hope this helps.

~Jurgen</span>

You might be interested in

Two large conducting parallel plates A and B are separated by 2.4 m. A uniform field of 1500 V/m, in the positive x-direction, i

Lapatulllka [165]

Answer:

a. 1.027 x 10^7 m/s b. 3600 V c. 0 V and d. 1.08 MeV

Explanation:

a. KE =1/2 (MV^2) where the M is mass of electron

b. E = V/d

c. V= 0 V (momentarily the pd changes to zero)

d KE= 300*3600 v = 1.08 MeV

6 0

2 years ago

How is sound produced? Name its three<br>characteristics.

nydimaria [60]

Answer:

1.loudness

2.pitch

3.shrillness

5 0

3 years ago

A pingpong ball has 2 kg m/s of momentum when thrown 8 m/s find the mass of the ball

avanturin [10]

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

4 0

1 year ago

#1 a person weighs 540n on earth what is the persons mass.

bixtya [17]

Answer:

G on earth =10N/Kg

W= mg

540= m x 10

m = 540/10

m= 54 Kg

W= mg

W= 66 x 10

W= 660 N

G on moon =1.6 N/Kg

W= mg

W= 54 x 1.6

W=86.4 N

W=mg

W= 66 x 1.6

W= 105.6 N

8 0

1 year ago

An 87.6 g lead ball is dropped from rest from a height of 7.00 m. The collision between the ball and the ground is totally inela

bija089 [108]

Taking specific heat of lead as 0.128 J/gK = c

We have energy of ball at 7.00 meter height = mgh = $87.6*10^{-3}*9.81*7$

When leads gets heated by a temperature ΔT energy needed = mcΔT

= $87.6*10^{-3}*0.128*10^3$ ΔT

Comparing both the equations

$87.6*10^{-3}*9.81*7$ = $87.6*10^{-3}*0.128*10^3$ ΔT

ΔT = 0.536 K

Change in temperature same in degree and kelvin scale

So ΔT = 0.536 $^0C$

7 0

2 years ago