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inn [45]
3 years ago
9

A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h

ow much did the machinist increase the feed rate
Physics
2 answers:
LekaFEV [45]3 years ago
6 0

Explanation:

Given that,

Current feed rate of a machine is 5.921 IPM

Final feed rate of the machine is 6.088 IPM

To find,

Increase in feed rate

Solution,

We need to find the increase in feed rate of the machine. It is calculated simply by subtracting final feed rate to the initial feed rate as :

Increase in feed rate = 6.088 IPM - 5.921 IPM

Increase in feed rate = 0.167 IPM

or

Increase in feed rate = 16.7 %

So, the increase in feed rate of the machine is 0.167 IPM or 16.7 %

lukranit [14]3 years ago
4 0

Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

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While bats emit a wide variety of sounds, one type emits pulses of sound at a frequency between 39 kHz and 78 kHz. What is the r
sdas [7]

Answer:

The range of wavelengths of the sound is 7692.30 m and 3846.15 m

Explanation:

A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.

Bat uses ultrasonic waves. It moves with the speed of light.

If f = 39 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{39\times 10^3}\\\\\lambda=7692.30\ m

If f = 78 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{78\times 10^3}\\\\\lambda=3846.15\ m

So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.

6 0
3 years ago
An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact wi
hoa [83]

Answer:

a)       a = 3.72 m / s², b)    a = -18.75 m / s²

Explanation:

a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

              v₂ = 60 km / h = 16.66 m / s

l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

            F Δt = m v_f - m v₀

            F = \frac{m ( v_f - v_o)}{t}

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

4 0
2 years ago
Evaluate tan(249).<br> O A. 1.36<br> B. 0.45<br> C. 0.41<br> D. 0.91
vodomira [7]

Answer:

tan 249 = 2.61

tan 249 = tan (249 - 180) = tan 69 = 2.61

3 0
2 years ago
an object is dropped from a height of 25 meters. at what velocity will it hit the ground? a 7.0 m/s b 11 m/s c 22 m/s d 49 m/s e
kipiarov [429]
Assuming that the object starts at rest, we know the following values:

distance = 25m
acceleration = 9.81m/s^2 [down]
initial velocity = 0m/s

we want to find final velocity and we don't know the time it took, so we will use the kinematics equation without time in it:

Velocity final^2 = velocity initial^2 + 2 × acceleration × distance

Filling everythint in, we have:

Vf^2 = 0^2 + (2)(-9.81)(-25)
The reason why the values are negative is because they are going in the negative direction

Vf^2 = 490.5

Take the square root of that

Final velocity = 22.15m/s which is answer c
6 0
3 years ago
What is the first law of conservation of energy? How is the law applicable to the earths energy balance
Vlad1618 [11]

Answer:

First law of thermodynamic state that energy is always conserved, in other word, energy cannot be created or destroyed.

This means that energy can only transfer from one source to another.

For example, the electricity we used to power our phone didn't come from nowhere.

We charge our phone using the energy from the electricity from the outlet.

The outlet gets its energy from the power plant, who generated that energy from burning coal.

The coal they burned got their energy while they were alive as plants.

The plants got their energy from the sun.

The sun got its energy from other cosmic stuff and so on...

My point is that the energy we use will always cycle around. It doesn't come from thin air and it doesn't disappear into thin air either. This help keeps things balance because if energy is created out of thin air then the earth might just blow up. If energy gets erased into thin air then there'll be nothing to fuel life.

5 0
3 years ago
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