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marysya [2.9K]
3 years ago
9

Scientists have detected an asteroid that is 700,000,000 km from Earth. About how many astronomical units is that? 0. 5 AU 1 AU

3. 5 AU 4. 5 AU.
Physics
2 answers:
Elza [17]3 years ago
6 0

Answer:

it is 4.67921098559 astronomical units

Explanation:

nalin [4]3 years ago
3 0

An asteroid that is 700,000,000 km is equivalent to 4.67 AU.

Option D is the correct answer.

<h3>How do you convert KM into AU?</h3>

Given that an asteroid that is 700,000,000 km from Earth.

We know that 1 AU is equal to 149597870.691 KM. The expression can be given below.

1 \;\rm AU = 149597870.691\;\rm KM

1 \;\rm KM =  \dfrac {1}{149597870.691} \;\rm AU

700,000,000 \;\rm KM = \dfrac {1}{149597870.691} \times 700,000,000 \;\rm AU

700,000,000 \;\rm KM = 4.67 \;\rm AU

Hence we can conclude that 700,000,000 km is equivalent to 4.67 AU. Option D is the correct answer.

To know more about the astronomical units, follow the link given below.

brainly.com/question/21464262.

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Over a period of operation, the useful work output of the fluorescent bulb was
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Object 1 of mass m moves with speed v in the positive direction. Object 2 of mass 3 m moves with speed 4 v in the negative x-dir
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Answer:

This means that the kinetic energy of second object is 48times that of the first object

Explanation:

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v is the velocity of the object

If Object 1 of mass m moves with speed v in the positive direction, its kinetic energy will be expressed as;

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For Object 2 of mass 3m moving with speed 4v in the negative x-direction, its kinetic energy can be expressed as;

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K2 = (3m)(8v²)

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To compare the kinetic energy of both bodies, we will take the ratio of K2:K1 to have;

K2/K1 = 24mv²/(1/2)mv²

K2/K1 = 24/(1/2)

K2/K1 = 48

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This means that the kinetic energy of second object is 48times that of the first object and moving in the negative x direction since the body of mass 3m initially moves in the negative x direction.

3 0
4 years ago
0. A 3.00-kg block is dropped from rest on a vertical spring whose spring constant is 750 N/m. The block hits the spring, compre
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Answer:

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Explanation:

Given data

mass = 3 kg

spring constant k = 750 N/m

vertical distance h = 0.45

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How far is the spring compressed

solution

we will apply here law of mass of conservation

i.e

gravitational potential energy loss = gain of eastic potential energy of spring

so we say m×g×h = 1/2× k × e²

so e² = 2×m×g×h / k

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so the spring compressed is 0.1878 m

5 0
3 years ago
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