Answer:
The correct option is a.
Explanation:

125 kPa
125kpa - 2x 4x x
Total pressure after reaction = 176 kPa
125 kPa - 2x + 4x + x = 176 kPa
x = 17
125 kpa - 2x = 125 kPa - 2(17) = 91 kPa
Initial pressure of the dinitrogen pentoxide ,(at t=0) =
Final pressure of the dinitrogen pentoxide, (at t = t) = P = 91 kPa
The rate constant is = 



It will take 113 minutes for the total pressure to reach 176 kPa.
Answer:
+4
Explanation:
Oxidation number of neutral compound is 0
Oxidation number of hydrogen in methane is -1
C + (-1×4) = 0
C - 4 = 0
C = 4
<h3>
Answer:</h3>
1.85 M
<h3>
Explanation:</h3>
<u>We are given;</u>
- Number of moles as 0.50 mol
- Volume of the solution is 270 ml
But, 1000 mL = 1 L
- Thus, volume of the solution is 0.27 L
We are required to calculate the molarity of the solution;
- Molarity refers to the concentration of a solution in moles per liter.
- It is calculated by dividing number of moles with the volume.
Molarity = Moles ÷ Volume
In this case;
Molarity = 0.50 moles ÷ 0.27 L
= 1.85 Mol/L or 1.85 M
Therefore, molarity of the solution is 1.85 M
Answer:
See the answer below
Explanation:
Even though plants are rooted in the ground, they still move, exert <u>force,</u> and do<u> work</u>.
Plant cells have very strong cell walls that allow <u>pressure</u> to build up inside of the cell as water is absorbed. This pressure is called <u>turgor</u>.
When turgor pressure is high enough in a cell, the cell walls become <u>firm</u> and as a result, the cell becomes rigid and the plant is able to stand <u>tall</u> and<u> straight</u>.
When a plant does not get enough water, the turgor pressure inside of the cells <u>decreases.</u> A decrease in <u>pressure</u> pushing against the cell wall causes the cells to lose their <u>shape</u> and <u>shrink</u>. This causes the plant to begin to droop or <u>wilt</u>.
When the wilted plant gets enough water, the cells will become rigid again, and the plant will stand firm and straight once again.
Answer:
One extraction: 50%
Two extractions: 75%
Three extractions: 87.5%
Four extractions: 93.75%
Explanation:
The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.
qⁿ = (V₁/(V₁ + KV₂))ⁿ
We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:
qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ = (V₁/(2V₁))ⁿ = (1/2)ⁿ
When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.
When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.
When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.
When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.