20. The mass of one mole of lead (Pb) atoms is 207.2 g. Use a proportion to calculate the n
1 answer:
Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) × ( Mw )
Explanation:
sample:
∴ m = 15.00 g
a) atoms Pb = ?
⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
⇒ atoms Pb = 4.3595 E22 amu
b) relationship:
∴ 1 mol (n) ≡ 6.022 E23 amu......(1)
∴ mass (g) ≡ (Mw)×(n)
⇒ n = g / Mw..........(2)
∴ Mw: molecular weight
(1) = (2):
⇒ g / Mw ≡ 6.022 E23 amu
⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )
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