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3 years ago

When 16.35 moles of SI reacts with 11.26 moles of N2, how many moles of SI3N4 are formed

Chemistry

1 answer:

Allushta [10]3 years ago

6 0

Answer:

5.450 mol Si₃N₄

Explanation:

Step 1: Write the balanced equation

3 Si + 2 N₂ ⇒ Si₃N₄

Step 2: Establish the theoretical molar ratio between the reactants

The theoretical molar ratio of Si to N₂ is 3:2 = 1.5:1.

Step 3: Establish the experimental molar ratio between the reactants

The experimental molar ratio of Si to N₂ is 16.35:11.26 = 1.45:1. Comparing both molar ratios, we can see that Si is the limiting reactant.

Step 4: Calculate the moles of Si₃N₄ produced from 16.35 moles of Si

The molar ratio of Si to Si₃N₄ is 3:1.

16.35 mol Si × 1 mol Si₃N₄/3 mol Si = 5.450 mol Si₃N₄

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Now put all the given values in the above formula, we get:

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3 years ago

Consider the equation: S+302 →SO3 Is this equation balanced? Why or why not?

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guajiro [1.7K]

Answer:

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