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LenKa [72]
4 years ago
15

50 POINTS!!!!!!!!!!!

Chemistry
2 answers:
Pani-rosa [81]4 years ago
6 0

Answer:

c

Explanation:

kifflom [539]4 years ago
5 0
A substitution is a mutation that exchanges one base for another. This can include a change in a single chemical letter. ex. changing a to g or in your case g to a. I believe the correct answer should be B.
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Heart attacks can cause sudden death.<br><br> True <br><br> False
rjkz [21]

Answer:

True

Explanation:

8 0
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Describe the stages of water cycle
lora16 [44]
Evaporation, Condensation, precipitation and collection would be stages
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A sample of hydrogen gas collected by displacement of water occupied 30mL at 24 C on a day when the barometric pressure was 736t
shusha [124]

Answer:

v_2=6,48*10^{-4}L

Explanation:

From the question we are told that:

Volume of hydrogen  V_1=30mL=>30*10^{-3}

Temperature T_1=24C=>24+273=>297k

Pressure of water P_1=22.4torr=>\frac{22.4}{760}=0.0295atm

Let

STP(Standard Temperature and pressure)

 T_2=273K

 P_2=1atm

Generally the equation for ideal gas is mathematically given by

 \frac{p_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Therefore

 v_2=\frac{P_1v_1T_2}{T_1P_2}

 v_2=\frac{0.0295*30*10^{-3}*273}{297*1}

 v_2=6.48*10^{-4}L (at STP(Standard Temperature and pressure))

6 0
3 years ago
When magnesium-28 undergoes beta decay, what is the identity and mass number of the nucleus formed?
Ugo [173]
 <span>Beta decay increases the atomic number by 1, and does not change the mass number. 28Mg12 → 0e-1 + 28Al13</span>
3 0
3 years ago
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Calculate the solubility of CaF2 in g/L (Ksp = 4.0 x 10-8). 2. What is the pH of a solution containing a hydrogen ion concentrat
Pepsi [2]

Answer:

\large \boxed{1. \text{ 0.17 g/L; 2. 3.52; 3. Cl; 4. (a) +3; (b) +4; (c) +6}}

Explanation:

1. Solubility of CaF_2

(a) Molar solubility

CaF₂ ⇌ Ca²⁺ + 2F⁻

K_{\text{sp }} = \text{[Ca$^{2+}$]}\text{[F$^{-}$]}^{2}= 4.0 \times 10^{-8}\\s(2s)^{2}=4.0 \times 10^{-8}\\4s^{3} = 4.0 \times 10^{-8}\\s^{3} = 1.0 \times 10^{-8}\\s =2.2 \times 10^{-3}\text{ mol/L}

(b) Mass solubility

\text{Solubility} = 2.2 \times 10^{-3} \text{ mol/L} \times \dfrac{\text{78.07 g}}{\text{1 L }} = \text{0.17 g/L}\\\\\text{The solubility of CaF$_{2}$ is $\large \boxed{\textbf{0.17 g/L}}$}

2. pH

pH = -log [H⁺] = -log(3.0 × 10⁻⁴) = 3.52

3. Oxidizing and reducing agents

Zn + Cl₂ ⟶ ZnCl₂

\rm \stackrel{\hbox{0}}{\hbox{Zn}} + \stackrel{\hbox{0}}{\hbox{ Cl}_{2} }\longrightarrow \stackrel{\hbox{+2}}{\hbox{Zn}}\stackrel{\hbox{-1}}{\hbox{Cl}_{2}}

The oxidation number of Cl has decreased from 0 to -1.

Cl has been reduced, so Cl is the oxidizing agent.

4. Oxidation numbers

(a) Al₂O₃

\stackrel{\hbox{$\mathbf{+3}$}}{\hbox{Al}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{3}}

1O = -2; 3O = -6; 2Al  = +6; 1Al = +3

(b) XeF₄

\stackrel{\hbox{$\mathbf{+4}$}}{\hbox{Xe}}\stackrel{\hbox{-1}}{\hbox{F}_{4}}

1F = -1; 4F = -4; 1 Xe = +4

(c) K₂Cr₂O₇

\stackrel{\hbox{${+1}$}}{\hbox{K}_{2}}\stackrel{\hbox{$\mathbf{+6}$}}{\hbox{Cr}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{7}}

1K = +1; 2K = +2; 1O = -2; 7O = -14

+2 - 14 = -12

2Cr = + 12; 1 Cr = +6

8 0
4 years ago
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