Volume of H₂O added = 175 ml
<h3>Further explanation</h3>
Given
100 gm of a 55% (M/M) and 20% (M/M) nitric acid solution
Required
waters added
Solution
starting solution
mass H₂O = 45%=45 g
%mass of H₂O in new solution = 100%-20%=80%
Can be formulated for %mass H₂O :

For water mass=volume(density = 1 g/ml)
So volume added = 175 ml
Answer:
C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP is the chemical equation for cellular respiration
Explanation:
Cellular respiration is the process by which cells breakdown glucose molecules to produce energy in the form of ATP molecules and release waste products such as carbon dioxide and water molecules. Cellular respiration involves a series of reaction pathways such as glycolysis, pyruvate oxidation, citric acid cycle and the oxidative phosphorylation pathway.
The first step of glycolysis breaks down a glucose molecule to release two pyruvate molecules.
In pyruvate oxidation, two molecules of pyruvate are oxidized to acetyl-CoA molecules.
In the citric acid cycle, the acetyl-CoA molecules are used to produce the electron carriers NADH and FADH2.
In the oxidative phosphorylation pathway, NADH and FADH2 donate their electrons to oxygen and ATP molecules are produced using the energy of electron transfer and proton-pumping.
The overall equation for cellular respiration is given as:
C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP
is the orbital hybridization of a central atom that has one lone pair and bonds to three other atoms.
<h3>What is
orbital hybridization?</h3>
In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.
For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.
Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.
Learn more about Hybridization
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<h3>
Answer:</h3>
0.424 J/g °C
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Chemistry</u>
<u>Thermochemistry</u>
Specific Heat Formula: q = mcΔT
- q is heat (in Joules)
- m is mass (in grams)
- c is specific heat (in J/g °C)
- ΔT is change in temperature
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] m = 38.8 g
[Given] q = 181 J
[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C
[Solve] c
<u>Step 2: Solve for Specific Heat</u>
- Substitute in variables [Specific Heat Formula]: 181 J = (38.8 g)c(11.0 °C)
- Multiply: 181 J = (426.8 g °C)c
- [Division Property of Equality] Isolate <em>c</em>: 0.424086 J/g °C = c
- Rewrite: c = 0.424086 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.424086 J/g °C ≈ 0.424 J/g °C