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3 years ago

I need help with my science.

Physics

1 answer:

Ostrovityanka [42]3 years ago

8 0

Answer:

1: 2

2: 5

Explanation:

hope this helps <3

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Por qué se celebra el día del deporte

yulyashka [42]

Answer:

Día Internacional del Deporte para el Desarrollo y la Paz, 6 de abril. El deporte ha desempeñado históricamente un papel importante en todas las sociedades, ya sea en forma de competiciones deportivas, de actividades físicas o de juegos. ... De hecho, el deporte es un socio natural para el sistema de la ONU.

Explanation:

7 0

3 years ago

A golf ball (m = 59.2 g) is struck a blow that makes an angle of 50.5 ◦ with the horizontal. The drive lands 130 m away on a fla

fomenos

Answer:

The force is calculated as 338.66 N

Explanation:

We know that force is given by

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{m(v_{f}-v_{o})}{\Delta t}$

We know that range of a projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{g}$

it is given that R=130 m applying values in the above equation we get

$R=\frac{v_{o}^{2}sin(2\theta )}{g}\\\\v_{0}=\sqrt{\frac{Rg}{sin(2\theta )}}\\\\\therefore v_{o}=\sqrt{\frac{130\times 9.81}{sin(2\times 50.5_{o}} )}\\\\v_{o}=36.04m/s$

Thus the force is obtained as

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{59.2\times 10^{}-3(36.04-0)}{6.3\times 10^{-3}}$

Thus force equals $F=338.66N$

4 0

3 years ago

Read 2 more answers

How much mass energy could be obtained from the complete conversion of a 235 g hamburger?

Radda [10]

E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶ kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J

8 0

3 years ago

Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i

xz_007 [3.2K]

Answer:

$E = 7.83 \times 10^5 N/C$

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

$E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}$