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3 years ago

Heat energy is transferred by conduction whenever molecules?

Physics

2 answers:

Rama09 [41]3 years ago

8 0

<em>The heat transfer by conduction occurs due to the collision between the molecules in the substance.</em>

Explanation:

The heat transfer between the substances or in a medium is carried out by means of three methods.

Conduction
Convection
Radiation

The conduction is the process of transfer of heat within the substance by transferring the heat one by one to each molecule throughout the substance by colliding with the neighboring molecule. This method prevails in the transfer of heat in the solids.

The convection is the process of transfer of heat in which the source of heat is used to heat a particular bunch of molecules or a layer of the substance and then that layer moves away from the source and lets other molecule to come close to the layer. This method of heating is used in liquids.

The radiation is the process of transfer of heat in the medium by means of the energy carried by the radiation. This process of heating is used for the heating of the gases in the medium.

Thus, <em>The heat transfer by conduction occurs due to the collision between the molecules in the substance.</em>

Learn More:

1. Which one is a compound machine brainly.com/question/9060219

2. Equinoxes occur when brainly.com/question/1000562

3. Explanation for the salinity of ocean water brainly.com/question/2752734

Answer Details:

Grade: Middle School

Subject: Physics

Chapter: Heat transfer

Keywords:

heat energy, transferred, conduction, convection, radiation, molecules, solids, liquids, medium, substance, transfer.

atroni [7]3 years ago

5 0

Answer:

collide.

Explanation:

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A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule

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(a) 0.165 m/s

The total initial momentum of the astronaut+capsule system is zero (assuming they are both at rest, if we use the reference frame of the capsule):

$p_i = 0$

The final total momentum is instead:

$p_f = m_a v_a + m_c v_c$

where

$m_a = 125 kg$ is the mass of the astronaut

$v_a = 2.50 m/s$ is the velocity of the astronaut

$m_c = 1900 kg$ is the mass of the capsule

$v_c$ is the velocity of the capsule

Since the total momentum must be conserved, we have

$p_i = p_f = 0$

$m_a v_a + m_c v_c=0$

Solving the equation for $v_c$ , we find

$v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s$

(negative direction means opposite to the astronaut)

So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

$F \Delta t = \Delta p$

The change in momentum of the astronaut is

$\Delta p= m\Delta v = (125 kg)(2.50 m/s)=312.5 kg m/s$

And the duration of the push is

$\Delta t = 0.600 s$

So re-arranging the equation we find the average force exerted by the capsule on the astronaut:

$F=\frac{\Delta p}{\Delta t}=\frac{312.5 kg m/s}{0.600 s}=520.8 N$

And according to Newton's third law, the astronaut exerts an equal and opposite force on the capsule.

(c) 25.9 J, 390.6 J

The kinetic energy of an object is given by:

$K=\frac{1}{2}mv^2$

where

m is the mass

v is the speed

For the astronaut, m = 125 kg and v = 2.50 m/s, so its kinetic energy is

$K=\frac{1}{2}(125 kg)(2.50 m/s)^2=390.6 J$

For the capsule, m = 1900 kg and v = 0.165 m/s, so its kinetic energy is

$K=\frac{1}{2}(1900 kg)(0.165 m/s)^2=25.9 J$

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