Select all that apply. All living things... <br><br> Can someone check this for me?

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

Inessa05 [86]

<h2>Hello!</h2>

The answer is: -97.37° C

According to the Charles and Gay-Lussac's Law we have that:

$\frac{V}{T}=k$

Where:

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

$\frac{V1}{T1}=\frac{V2}{T2}$

Since we need to find the new temperature (T2) we can use the last equation:

$\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K$

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

$Celsius=K-273.15=175.92-273.15=-97.37$

So, the temperature is -97.37° C

Have a nice day!

7 0

3 years ago

Help please with question number 16)

Zanzabum

Answer:

Mg²⁵ = 10.00%

Mg²⁶ = 45.04%

Mg²⁴ = 44.96%

Explanation:

Given data:

Atomic mass of Mg²⁶ = 25.983

Atomic mass of Mg²⁵ = 24.986

Atomic mass of Mg²⁴ = 23.985

Abundance of Mg²⁵ = 10.00%

Abundance of Mg²⁶ = ?

Abundance of Mg²⁴ = ?

Solution:

Average atomic weight of Mg = 25.983 + 24.986+ 23.985 / 3

Average atomic weight of Mg = 74.954/3

Average atomic weight of Mg = 24.985 amu

Abundance of

Mg²⁵ = 10.00

Mg²⁶ = x

Mg²⁴ = 100- 10 - x = 90 -x

Formula:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100

24.985 = (0.1×24.986)+(90-x×23.985) + ( x ×25.983 ) /100

24.985 = 249.86 + 2158.65 - 23.985x + 25.983x / 100

24.985 = 2408.51 + 1.998 x / 100

2498.5 = 2408.51 + 1.998 x

1.998 x = 2498.5 - 2408.51

1.998 x = 89.99

x = 89.99 /1.998

x = 45.04

Now we put the value of x:

Mg²⁵ = 10.00

Mg²⁶ = x (45.04)

Mg²⁴ = 90 -x (90 - 45.04 = 44.96)

5 0

3 years ago

4. If an experimental value for a given observation was 415 nm while the theoretical value

Alex

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

7 0

3 years ago

Consider the following reaction

aliina [53]

Answer:

d, 40 dm3.

Explanation:

According to Avogadro's law, the mole ratio of chemicals in a reaction is equal to the ratio of volumes of chemicals reacted (for gas).

From the equation, the mole ratio of N2 : H2 : NH3 = 1 : 3 : 2, meaning 1 mole of N2 reacts completely with 3 moles of H2 to give 2 moles of NH3, the ratio of volume required is also equal to 1 : 3 : 2.

Considering both N2 and H2 have 30dm3 of volume, but 1 mole of N2 reacts completely with 3 moles of H2, so we can see H2 is limiting while N2 is in excess. Using the ratio, we can deduce that 10dm3 equals to 1 in ratio (because 3 moles ratio = 30dm3).

With that being said, all H2 has reacted, meaning there's no volume of H2 left. 2 moles of NH3 is produced, meaning the volume of NH3 produced = 10 x 2 = 20 dm3. (using the ratio again)

1 mole of N2 has reacted, meaning from the 30dm3, only 10 dm3 has reacted. This also indicate that 20 dm3 of N2 has not been reacted.

So at the end, the mixture contains 20dm3 of NH3, and 20 dm3 of unreacted N2. Hence, the answer is d, 40 dm3.

7 0

3 years ago

Explain the three types of cumbusion ??

Alik [6]

Answer:

Complete Combustion

One of the types of combustion is Complete Combustion. Complete combustion occurs in an unlimited supply of air, oxygen in particular. Also, complete combustion is also known as clean combustion. Here the hydrocarbon will burn out completely with the oxygen and leave only two byproducts, water, and carbon dioxide.

An example of this is when a candle burns. The heat from the wick will vaporize the wax which reacts with the oxygen in the air. The two products of the reaction are water and carbon dioxide. In an ideal situation all the wax burns up and complete combustion takes place

2] Incomplete Combustion

Incomplete combustion takes place when the air is in limited supply. And as opposed to complete combustion it is otherwise known as dirty combustion. Due to lack of oxygen, the fuel will not react completely. This, in turn, produces carbon monoxide and soot instead of carbon dioxide.

An example is burning of paper. It leaves behind ash (a form of soot) as a byproduct. In a complete combustion, the only products are water and carbon dioxide. Also, incomplete combustion produces less energy than complete combustion.

3] Rapid Combustion

Another type of combustion is Rapid Combustion. Rapid energy needs external heat energy for the reaction to occur. The combustion produces a large amount of heat and light energy and does so rapidly. The combustion will carry on as long as the fuel is available.

An example is when you light a candle. The heat energy is provided when we light the candle with a matchstick. And it will carry on till the wax burns out. Hence it is a rapid combustion

4] Spontaneous Combustion

As the name suggests the combustion occurs spontaneously. This means that it requires no external energy for the combustion to start. It happens due to self-heating. A substance with low-ignition temperatures gets heated and this heat is unable to escape.

The temperature rises above ignition point and in the presence of sufficient oxygen combustion will happen. The reaction of alkali metals with water is an example.

5] Explosive Combustion

Explosive Combustion happens when the reaction occurs very rapidly. The reaction occurs when something ignites to produce heat, light and sound energy, The simple way to describe is it to call it an explosion. Some classic examples are firecrackers or blowing up of dynamite.

6 0

2 years ago

Select all that apply. All living things... Can someone check this for me?