We should describe a little bit the legend.
A - Element - we should have circles with same color and not bonded together (argon gas).
B - Compound - here we may have circles with same or different color bonded together (water or oxygen which is a diatomic molecule).
C - Mixture of elements - circles with different colors not not bonded together (mixture of noble gases).
D - Mixture of compounds - circles with same or different color bonded together but we should see two or more types of connectivity between circles (mixture of water and ethanol).
E - Mixture of elements and compounds - circles with same or different color bonded together mixed with circles with same color and not bonded together (a mixture between oxygen which is a diatomic molecule and noble gas like argon).
Now we may answer the question:
1) B
2) C
3) D
4) D
5) A
6) B
7) B
8) E
9) E
10) D
11) B
12) D
13) D
14) D
15) D
Answer:
The correct option is: B. Carbon 5 only
Explanation:
Carvone is a naturally-occurring monoterpenoid consisting of a six-membered cyclic ring. <u>The </u><u><em>carbon-5</em></u><u> of this cyclic ring of Carvone is </u><u><em>chiral, </em></u><u>due to which Carvone exhibits </u><u><em>enantiomerism</em></u><u>.</u>
The two <em>enantiomeric forms</em> of Carvone are: R-(–)-carvone, or L-carvone, and S-(+)-carvone, or D-carvone.
<em><u>These two enantiomeric forms differ in the orientation of the substituents on the chiral carbon-5.</u></em>
<u />
<u>Therefore, the correct option is B. Carbon 5 only.</u>
On the periodic table everything to the right of the line is a non metal
Everything to the left is a metal. So the line crosses to the right is NM to left is M
