Answer:
Energy, E = 18 kJ
Explanation:
Given that,
Power of the lightbulb, P = 5 W
We need to find the electrical energy produced by the lightbulb in one hour. We know that electric power is given by the electrical energy produced per unit time.
1 hour = 3600 seconds
Electric power :
or
E = 18 kJ
So, 18 kJ of electrical energy a 5-W lightbulb convert to radiant and thermal energy in one hour.
Here,
height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,
<span>
SO, </span>
<span>
v^2 = 2*a*h = 2*2.25*525 = 2362.5 </span>
Now, acceleration, g = 9.8 m/s^2,
<span>
SO, </span>
<span>
heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters </span>
Hence,
<span>
a) </span>
Total height = 525+120.54 = 645.54 meters
b)
<span>time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec
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Answer:
C
Explanation:
Rt= total resistance
we know that 1/Rt=1/R1+1/R2(from ohm's law)
Since, Rt=4 and R1=R2
we will get,
1/4=2/R2
R2=8
when in series Rt=R1+R2,
So, Rt=8+8=16 ohm's
Insert moves the insertion point to the beginning of data in a cell so the answer is INSERT :)))
i hope this be helpful
