Question

12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?

Answer 1

Answer:

$u=4.57x10^5GHz$

Explanation:

Hello.

In this case, given the formula:

$E=h*u$

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

$u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\ \\u=4.57x10^{14}s^{-1}$

Or also:

$u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz$

Best regards.